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Arada [10]
3 years ago
6

1The density of an of an object with a volume of 60.0 and mass of 400.0g is______

Physics
1 answer:
Kobotan [32]3 years ago
4 0
D is the answer
To get the density you divide mass by volume
So the equation is 400/60=d
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A student has been assigned to measure the density of an irregularly shaped piece of metal.which apparatus would be more appropr
SOVA2 [1]

Complete Question:

A student has been assigned to measure the density of an irregularly shaped piece of metal.

Which apparatus would be most appropriate to carry out this task?

Group of answer choices

A. ruler, balance

B. beaker, crucible

C. flask, Bunsen burner

D. graduated cylinder, balance

Answer:

D. graduated cylinder, balance

Explanation:

In this scenario, A student has been assigned to measure the density of an irregularly shaped piece of metal.

The apparatus which would be most appropriate to carry out this task is a graduated cylinder and balance.

A graduated cylinder can be defined as a measuring cylinder used for the measurement of the volume of an irregularly shaped piece of metal or liquids. It is typically marked with horizontal lines on its side as units of measurement for volume. The balance is then used to weigh the metals mass.

3 0
3 years ago
se lanza un cuerpo desde el origen con velocidad horizontal de 40 m/s, y con un ángulo de 60º. calcular la máxima altura y el al
EastWind [94]

Answer:

1. h = 244.8 m    

2. x = 564.8 m  

Explanation:

1. La altura máxima se puede calcular usando la siguiente ecuación:

v_{f}^{2} = v_{0}^{2} - 2gh     (1)                        

Where:

v_{f_{y}}: es la velocidad final = 0 (en la altura máxima)  

v_{0_{y}}: es la velocidad inicial horizontal en "y"

g: es la gravedad = 9.81 m/s²          

h: es la altura máxima =?

La velocidad incial en "y" se puede calcular de la siguiente manera:

tan(\theta) = \frac{v_{0_{y}}}{v_{0_{x}}}

v_{0_{y}} = tan(60)*40 m/s = 69.3 m/s                    

Resolviendo la ecuación (1) para "h" tenemos:

h = \frac{v_{0_{y}}^{2}}{2g} = \frac{(69.3 m/s)^{2}}{2*9.81 m/s^{2}} = 244.8 m          

2. Para calcular el alcance horizontal podemos usar la ecuación:

x = v_{x}*t

Primero debemos encontrar el tiempo cuando la altura es máxima (v_{f_{y}} = 0).

v_{f_{y}} = v_{0_{y}} - gt    

t = \frac{v_{0_{y}}}{g} = \frac{69.3 m/s}{9.81 m/s^{2}} = 7.06 s      

Ahora, como el tiempo de subida es el mismo que el tiempo de bajada, el tiempo máximo es:

t_{m} = 2*7.06 s = 14.12 s          

Finalmente, el alcance horizontal es:

x = 40 m/s*14.12 s = 564.8 m                                                            

Espero que te sea de utilidad!

7 0
3 years ago
Have some fr/ee points because i finished highschool today :)
Aleks04 [339]

Answer:

Thank you :)

Explanation:

And congrats on finishing !!

3 0
3 years ago
Witch unit is used to measure mass in the metric system
Alecsey [184]
The gram (g)
a nickel weighs 5 grams, and a raisin weighs approximately 1 gram.
There is also the kilogram(kg), or 1000 grams
6 0
3 years ago
Read 2 more answers
The graph shows two runners participating in a race.
qaws [65]

The answer is the first one, Daniela has a 5 meter head start but leonard caught up to her.

3 0
3 years ago
Read 2 more answers
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