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ratelena [41]
3 years ago
5

What events caused the formation of most islands in the South Pacific?

Chemistry
1 answer:
WINSTONCH [101]3 years ago
7 0
D. Volcanoes formed most of them through eruption.
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Are properties such as odor, color, density, and solubility physical or chemical properties?
storchak [24]
Physical properties- color, density, solubility.
<span>Chemical property- odor.

</span>You see, a physical property<span> is any property that can be </span>measured<span> , and a one that </span><span>describes the state of the physical system.
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https://socratic.org/questions/are-properties-such-as-odor-color-density-and-solubility-physical-or-...
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What is the difference between a theory and a law?​
kondaur [170]

Answer:

theory is diffrent from law

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a Theory can never be proven to be true nd a law can usually be expressed

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3 years ago
Mrs.Jacobs dropped an object from 10 meters she knows it did 50 joules of work how much did it weigh?
Alenkasestr [34]
It is 30 hope it help's.
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What is solar energy?
IrinaVladis [17]

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6 0
3 years ago
He isotope 62(over28ni has the largest binding energy per nucleon of any isotope. calculate this value from the atomic mass of n
irina [24]
The atomic mass of the isotope Ni ( 62 over 28 ) = 61.928345 amu.
Mass of the electrons: 28 · 5.4584 · 10^(-4 ) amu = 0.0152838 amu ( g/mol )
Mass of the nuclei:
61.928345 amu - 0.0152838 amu = 61.913062 amu (g/mol)
The mass difference between a nucleus and its constituent nucleons is called the mass defect.
For Ni ( 62 over 28 ): Mass of the protons: 28 · 1.00728 amu = 28.20384 amu
Mass of the neutrons: 34 · 1.00866 amu = 34.299444 amu
In total : 62.49828 amu
The mass defect = 62.49828 - 61.913062 = 0.585218 amu
Nucleus binding energy:
E = Δm · c² ( the Einstein relationship )
E = 0.585218 · ( 2.9979 · 10^8 m/s )² · 1 / (6.022 · 10^23) · 1 kg / 1000 g =
= 0.585218 · 8.9874044 · 10 ^16 : (6.022 · 10^23) · 0.001 =
= ( 5.2595908 : 6.022 ) · 0.001 · 10^(-7 ) =
= 0.0008733 · 10^(-7) J = 8.733 · 10^(-11) J
The nucleus binding energy per nucleon:
8.733 · 10^(-11) J : 62 =  0.14085 · 10 ^(-11) =
= 1.4085 · 10^(-12) J per nucleon.
4 0
3 years ago
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