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Bad White [126]
3 years ago
13

Given h(x)=2x-1 and g(x)=x^2+5, find (h/g) (x)

Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Step-by-step explanation:

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Which of the equations below could be the equation of this parabola?
Aleonysh [2.5K]

Answer:

C. x=-3y^2

Step-by-step explanation:

The group of parabola opens left so, x=ay^2

parabola opens left so a in negative x=-3y^2

Hope it helps....

8 0
3 years ago
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Which equation represents a line which is perpendicular to the line y=-4/5x+2?
lyudmila [28]

Answer:

D) 4x + 5y = -30 = -4/5

Step-by-step explanation:

A) 5x + 4y = 28 slope = -5/4

b) 4x-5y = -25 slope = 4/5

c) 4y - 5x = -12 slope = 5/4

d) 4x + 5y = -30 slope = -4/5

5 0
2 years ago
I will give BRAINLIEST
maria [59]
Give it to me please
7 0
3 years ago
What do i do please help!
Art [367]

Answer:

Step-by-step explanation:

this is confusing b/c they are asking about two trains traveling at differnt speeds, but.. if you put the speeds together and make one train... imaginary.. ofc... traveling at the speed of both trains combined... when will it be 50 miles from the station?

maybe you can solve that?   I'll solve it below.. but.. if you can.. try it now, on your own

below is my answer... don't look until you have solved yours :P

80+70= 150kph

when will this have traveled 50Km?

you may be able to see that it will take 1/3 of an hour to travel 50 km

so 60 minutes times 1/3 = 20 minutes  :)

8 0
3 years ago
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