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Ainat [17]
3 years ago
6

Someone help me quickkkkkkkkkkkkkk

Chemistry
1 answer:
Nana76 [90]3 years ago
5 0
The picture isn’t loading smh
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When someone opens a bottle of carbonated drinks, the pressure inside the bottle decreases.
Mekhanik [1.2K]

Answer:

When you open the bottle, there is a dramatic decrease in pressure over the liquid, so the CO2 starts to leave the liquid very rapidly, causing the mass exodus of gas, or "explosion" of bubbles. This also explains why soda goes flat.

Explanation: HOPE THIS HELPS YOU..

8 0
2 years ago
HELP ASAP PLS!!!!!!!!!!!!!!!!!!!!!!!
Rudiy27

Answer:correcting errors

Explanation:

5 0
3 years ago
How many molecules of CaCl2 are equivalent to 75.9 g CaCl2
sergij07 [2.7K]
First, you need to find:
One mole of CaCl_{2} is equivalent to how many grams?

Well, for this you have to look up the periodic table. According to the periodic table:
The atomic mass of Calcium Ca = 40.078 g (See in group 2)
The atomic mass of <span>Chlorine Cl = 35.45 g (See in group 17)
</span>
As there are two atoms of Chlorine present in CaCl_{2}, therefore, the atomic mass of CaCl_{2} would be:

Atomic mass of CaCl_{2}  = Atomic mass of Ca + 2 * Atomic mass of Cl

Atomic mass of CaCl_{2} = 40.078 + 2 * 35.45 = 110.978 g

Now,

110.978 g of CaCl_{2} = 1 mole.
75.9 g of CaCl_{2} = \frac{75.9}{110.978} moles = 0.6839 moles.

Hence,
The total number of moles in 75.9g of CaCl_{2} = 0.6839 moles

According to <span>Avogadro's number,
1 mole = 1 * </span>6.022 * 10^{23} molecules
0.6839 moles = 0.6839 * 6.022 * 10^{23} molecules = 4.118*10^{23} molecules

Ans: Number of molecules in 75.9g of  CaCl_{2} =  4.118*10^{23} molecules

-i


3 0
3 years ago
Read 2 more answers
How many atoms are in 6.3 moles of calcium
KIM [24]
1 mol --------- 6.02x10²³ atoms
6.3 moles ---- ??

atoms = 6.3 * 6.02x10²³

= 3.7926x10²⁴ atoms

hope this helps!
6 0
3 years ago
If the reaction of 9.87 moles of potassium with excess hydrobromic acid produced a 79.8% yield of hydrogen gas, what was the act
Fed [463]
Answer is: 3,94 of hydrogen gas.
Chemical reaction: 2K + 2HBr → 2KBr + H₂.
n(K) = 9,87 mol.
n(H₂) = ?.
from reaction: n(K) : n(H₂) = 2 : 1.
9,87 mol : n(H₂) = 2 : 1
n(H₂) = 4,935 mol for 100% yield of reaction
n(H₂) = 4,935 · 0,798 = 3,94 mol for 78,9 % yield of reaction.
n - amount of substance
7 0
3 years ago
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