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Komok [63]
1 year ago
7

Question 2Classify the following organic structures:CH3OCH3CH2CH2CHCH2CH3CH3NHCH3CH3CH(OH)CH₂CH3

Chemistry
1 answer:
Naily [24]1 year ago
3 0

Within the options, we have four organic compounds. Let's see what the skeletal structure of the compounds is in order to identify them better:

The first compound CH3OCH3 has two methyl groups linked by a carbon atom, this type of compound is called an Ether

The second compound has a double bond, it is badly written but it seems that is an alkene.

The third compound has two methyl groups linked by nitrogen atoms, therefore will be an amine.

The last compound has a hydroxyl group, therefore it is an alcohol

Answer:

CH3OCH3 Ether

CH2CH2CHCH2CH3 Alkene

CH3NHCH3 Amine

CH3CH(OH)CH₂CH3 Alcohol

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Calculate the number of O atoms in 0.364 g of CaSO4 · 2H2O
Nikolay [14]

Answer:

<em>= 7.66 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

Explanation:

For problems like this posting, one needs an understanding of the following topics:

The definition of the mole

<u>1 mole of substance</u> = mass in grams of substance containing 1 Avogadro's Number ( = 6.023 x 10²³ ) of particles of the specified substance. This is generally one formula weight of the substance of interest. From this, the following equivalent relationships should be memorized:

<em>   1 mole = 1 formula weight = 1 mole weight (g)= 6.023 x 10²³ particles</em>

Converting grams to moles:

<em>Given grams => moles = grams/gram formula wt </em>

Converting moles to grams:

<em>Given moles => grams = moles x gram formula wt</em>

_________________________________________________________

<em>Calculate the number of O atoms in 0.364 g of CaSO₄ · 2H₂O.</em>

Given mass CaSO₄ · 2H₂O = 0.364 grams

Formula Wt CaSO₄ · 2H₂O = 172 g/mole

moles CaSO₄ · 2H₂O = mass <em>CaSO4 · 2H2O / formula Wt. CaSO₄ · 2H₂O</em>

<em>= 0.364 g CaSO₄·2H₂O </em><em>/ </em><em>172 g CaSO4·2H2O </em>

<em>= (0.364/172) mole CaSO₄·2H₂O </em>

<em>= 2.12 x 10⁻³ mole CaSO₄·2H₂O    </em>

<em>∴ number of Oxy (O) atoms in 0.364 grams CaSO₄·2H₂O </em>

<em>=  (2.12 x 10⁻³ mole CaSO₄ · 2H₂O)(6.023 x 10²³ molecules CaSO₄· 2H₂O/ mole)</em>

<em>= 1.276876 x 10²¹molecules CaSO₄· 2H₂O  CaSO₄2H₂O </em>

<em>= 1.276876 x 10²¹ molecules CaSO₄· 2H₂O   x   6 oxygen atoms / molecule</em>

<em>= 7.661256 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

<em>= 7.66 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

<em />

8 0
2 years ago
What is the Sequence the different segments of the visible spectrum in order from shortest wavelength to
omeli [17]

Answer:The electromagnetic spectrum includes, from longest wavelength to shortest: radio waves, microwaves, infrared, optical, ultraviolet, X-rays, and gamma-rays.

Explanation:

5 0
2 years ago
Chromium(III) oxide reacts with hydrogen sulfide (H2S) gas to form chromium(III) sulfide and water:
natima [27]

Answer:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

Explanation:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

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3 0
2 years ago
Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below.2HgO Righ
Dimas [21]

Answer: 15.62 moles of HgO are needed to produce 250.0 g of O_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{250.0g}{32g/mol}=7.812moles

2HgO\rightarrow 2Hg+O_2

According to stoichiometry :

1 mole of O_2 is produced from decomposition of =  2 moles of HgO

Thus 7.812 moles of O_2 will be produced from decomposition of  =\frac{2}{1}\times 7.812=15.62moles of HgO

Thus 15.62 moles of HgO are needed to produce 250.0 g of O_2

7 0
3 years ago
What mass of nickel (Ni) is in a 2.4 Kg sample of propanol if the concentration is 20 ppb ? (atomic mass of Ni = 58.69)
asambeis [7]

Answer:

The mass of nickel is 48μg

Explanation:

Parts per billion is a way to describe small concentrations and is defined as the ratio between μg of solute and kg of solvent.

If a solution of nickel in propanol is 20ppb, contains 20μg of nickel in 1 kg of propanol.

Thus, a sample of 2.4kg of propanol will contain:

2.4kg × (20μg nickel / 1kg) = 48μg nickel

<h3>The mass of nickel is 48μg</h3>
8 0
3 years ago
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