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3 years ago

11

In the reaction between bromine and sodium, a bromine atom gains an electron and forms the bromide ion, Br-. What happens to bro

mine?

1 answer:

AlekseyPX3 years ago

6 0

It becomes ionized and attains its stable electronic configuration.

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The amount of energy in the bonds of the reactants plus any energy absorbed equals the amount of energy in the bonds of the prod

allochka39001 [22]

The answer to this question is Released
This is the law of energy conservation that being done in order to reduce the total consumption of energy by using less energy.
In most cases, the conservation requires either by using the intial energy more efficiently or by reducing the total result of the energy formed.

4 0

3 years ago

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The density of a certain type of plastic is 0.81 g/cm3. If a sheet of this plastic is 10.0 m long, 1.0 m wide, and 1 cm thick, w

crimeas [40]

<u>Answer:</u> The mass of plastic sheet is $8.1\times 10^4g$

<u>Explanation:</u>

The plastic sheet is in the form of cuboid. To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.0 m = 1000 cm (Conversion factor: 1 m = 100 cm)

b = breadth of cuboid = 1.0 m = 100 cm

h = height of cuboid = 1 cm

Putting values in above equation, we get:

$V=1000\times 100\times 1=10^5cm^3$

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of plastic sheet = $0.81g/cm^3$

Volume of plastic sheet = $10^5cm^3$

Putting values in equation 1, we get:

$0.81g/cm^3=\frac{\text{Mass of plastic sheet}}{10^5cm^3}\\\\\text{Mass of plastic sheet}=8.1\times 10^4g$

Hence, the mass of plastic sheet is $8.1\times 10^4g$

8 0

3 years ago

A scientist is unsure about the accuracy of her experiment. She has checked her equipment and found it to be in good working ord

Shkiper50 [21]

Answer:

repeat the experiment

Explanation:

I am big brain. if she wants to know if it is correct, repeating the exact ay would show her if it is right or if she did something wrong

4 0

3 years ago

Key terms: Reset ____________ anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. ____________ tautomers

iogann1982 [59]

Answer:

Acetylide , Enol ,aldehydes, tautomers, alkynes , Hydroboration, Keto

Explanation:

Reset <u>Acetylide</u> anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. <u>Enol </u>tautomers have an O-H group bonded to a C=C. <u>aldehydes </u>are formed from terminal alkynes with the addition of water using BH3 then H2O2. <u>tautomers</u> are constitutional isomers that differ in the location of a double bond and a hydrogen and exist in an equilibrium with each other. <u>alkynes</u> are compounds that contain a carbon-carbon triple bond. <u>Hydroboration</u> of a terminal alkyne adds BH₂ to the less substituted, terminal carbon.<u> Keto</u> tautomers have a C=O and an additional C-H bond.

3 0

3 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o

Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

$Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}$

Now, we are able to solve for m:

$m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} } = 9.70*10^4 g Na=97 Kg Na$ =97 000 g Na

7 0

3 years ago

Read 2 more answers