Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K
Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?
Use the general gas equation;
P1*v1/T1 = P2*v2/T2
As, the temperature is constant;
So,
v1/T1 = v2/T2
417/278 = v2/231
v2= 346.5 cm³
Look at the liter man it’s a great way to learn how much every liquid measurement is
Hi, your answer is correct.
Answer:
24 atoms of H or 1.4 x 10²⁵ hydrogen atoms
Explanation:
simple method
1 H₂O has atoms of hydrogen and 1 atom of oxygen
while 12H₂O will have 24 atoms of hydrogen and 12 atom of oxygen
by Avagadros number
molar mass of water H₂0=18.01528 g/mol
1 mole of H₂0 have 2 moles of Hydrogen
one mole of water= 6.02⋅10²³water molecules =1.2 x 10²⁴hydrogen atoms
12 mole of H₂O = 1.2 x 10²⁴ x 12= 1.4 x 10²⁵ hydrogen atoms
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1.4 x 10²⁵ hydrogen atoms in 12 moles of H₂O
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