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ankoles [38]
2 years ago
15

7. What item is a retail product?

Chemistry
2 answers:
Diano4ka-milaya [45]2 years ago
4 0
A car tire, it’s the only thing you can resale :)
Burka [1]2 years ago
3 0

Answer:

Car tire

Explanation:

it's a physical item

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PLEASE HELP ME!!! NEED THE ANSWER FAST! WILL CHOOSE THE BRAINLIEST!!!
Vlad [161]
Remember that a cation will be smaller than its neutral atom, and an anion will be larger than its neutral atom. This would automatically eliminate answer choices A and D.

Also keep in mind that atomic radii decreases from left to right as you move along a periodic table. It also decreases from bottom up. 
Atomic radii increases as you move from right to left and as you go from up to down.

As bromine is higher up in the periodic table than Iodine, it would have a smaller radius. Iodine would have a larger radius.

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8 0
3 years ago
Lithium (Li) and oxygen (O) are both in period 2. They both have? a.similar properties
xeze [42]
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3 years ago
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A brick has a mass of 4.0 kg and the Earth has a mass of 6.0 × 1027 g. Use this information to answer the questions below. Be su
Vedmedyk [2.9K]

Answer:

a) 2.4\times 10^{24} kg is the mass of 1 mole of bricks.

b) 2.5\times 10^3 moles of bricks have a mass equal to the mass of the Earth.

Explanation:

a) Mass of brick = 4.0 kg

1 mole = N_A=6.022\times 10^{23} particles/ atoms/molecules

Mass of N_A bricks :

=6.022\times 10^{23}\times 4.0 kg=2.4088\times 10^{24} kg\approx 2.4\times 10^{24} kg

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b)

Mass of the Earth = M = 6.0\times 10^{27} kg

Mass of 1 mole of brick = m=2.4\times 10^{24} kg

Let the moles of brick with equal mass of the Earth be x.

m\times x=M

x=\frac{M}{m}=\frac{6.0\times 10^{27}kg}{2.4\times 10^{24} kg}=2.5\times 10^3

2.5\times 10^3 moles of bricks have a mass equal to the mass of the Earth.

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Under what conditions is the change in internal energy, δe rxn , equal to the heat evolved in a chemical reaction?
Stells [14]
 the first law says that  the change in internal energy of a system is given by: 

δ<span>E = δq + δw</span>

where δ<span>E is the i change in internal energy, </span>

<span>δq is the amount of thermal energy added to the system from the surroundings </span>

<span>δw is the l work done *on* the system *by* the surroundings. </span>

<span>For a system only undergoing expansion work,
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δE = δq - p δ<span>V </span>
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