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VladimirAG [237]
4 years ago
7

1.What zodiac sign is October 19,2006? A). Sagittarius B). Libra C). Leo D). Pisces

Chemistry
2 answers:
NARA [144]4 years ago
7 0

Answer:

Libra

Explanation:

Libra is from September 23 to October 22

<u>Answered by me ofccc </u>

<em>Add me on Brainly and Padlet at </em><u><em>chuche17✌️</em></u><em> </em>

MrMuchimi4 years ago
5 0

Answer:

B. Libra

Explanation:

Libra's range from September 23rd to October 22nd

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strojnjashka [21]
C12H<span>22O</span>11 is the formula
7 0
3 years ago
If 14 moles of gas are added to a container that already holds 1 mole of gas, the pressure inside the container _ due to change
ioda

Answer:

The pressure inside the container will increase by increasing the amount of gas.

Explanation:

It can be better understand through ideal gas equation,

PV = nRT

By keeping the volume and temperature constant, the pressure of gas in container will increase when amount of gas goes to increase.

PV = nRT

P = nRT / V

P = (1+ 14) RT/V

P = 15

The pressure will increase 15 fold.

3 0
3 years ago
If the solubility of a N30 gas is 2.26g/l at 1.26atm of pressure, what is the solubility of
natali 33 [55]
The answer for your question is 0.27g/L
5 0
3 years ago
How many grams are in 1.946 moles of nacl
Ilia_Sergeevich [38]

Answer:

113.8g

Explanation:

Statement of problem: mass of 1.946mole of NaCl

Given parameters:

Number of moles of NaCl = 1.946mole

Unknown: mass of NaCl

Solution

To find the mass of NaCl, we apply the concept of moles which expresses the relationship between number of moles and mass according to the equation below:

                        Number of moles = \frac{mass}{molar mass}

To find the molar mass of NaCl:

                         the atomic mass of Na = 23g

                                atomic mass of Cl = 35.5g

                Molar mass of NaCl = (23 + 35.5) = 58.5gmol⁻¹

Mass of NaCl = Number of moles x molar mass of NaCl

Mass of NaCl = 1.946 x 58.5 = 113.8g

7 0
3 years ago
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-
hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written betweenZn^{2+} (Positive ion)and F^{-} (Negative ion)

First Formula would be ZnF_{2}

Second empirical formula is between Zn^{2+}(Positive ion) and O^{2-}(Negative ion)

Second Formula would be Zn_{2}O_{2}

Note : When the subscript are same they get cancel out, so Zn_{2}O_{2} would be written as ZnO

Third empirical formula is between Ni^{4+}(Positive ion) and F^{-}(Negative ion)

Third Formula would be :NiF_{4}

Forth empirical formula is between Ni^{4+}(Positive ion)and O^{2-}(negative ion)

Forth Formula would be : Ni_{2}O_{4} or NiO_{2}

Note- The subscript will be simplified and the formula will be written as NiO_{2}.

The empirical formula of four binary ionic compounds are : ZnF_{2}, ZnO, NiF_{4},NiO_{2}


8 0
3 years ago
Read 2 more answers
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