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Kazeer [188]
1 year ago
9

what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?

Chemistry
1 answer:
Law Incorporation [45]1 year ago
4 0

A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is (M1V1 = M2V2).

Utilize the titration method of M1V1 = M2V2 in view that we're given the concentrations of every compound and the quantity of KOH. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

  • M1 = initial mass
  • V1= initial volume
  • M2 = final mass
  • V2= final volume
  • (M1V1 = M2V2)
  • (0.138)(V1) = (0.205)x(26.0)
  • V2=(0.205)x(26.0)\ 0.138
  • V2 = 47.10 M/L
  • The final value of Volume needed for neutralization of nitric acid solution is  V2 = 47.10 M/L

Read more about the neutralization:

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Pi = xi P

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The mole fraction <u>is defined as the quotient between the moles of solute (ni) and the total moles of the mixture (nt)</u>, which is calculated by adding the moles of all its components:

xi = \frac{n_{i} }{n_{t} }

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To calculate the total number of moles of the mixture and thus determine the molar fraction of helium, we consider 100 g and calculate the number of moles that represent 10 g of O₂ (n₁), 50 g of He (n₂) and 40 g of N₂ (n₃):

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