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DerKrebs [107]
3 years ago
13

A sample of aluminum, which has a specific heat capacity of 0.897·J·g−1°C^−1 , is put into a calorimeter (see sketch at right) t

hat contains 300.0g of water. The aluminum sample starts off at 94.5°C and the temperature of the water starts off at 21.0°C .When the temperature of the water stops changing it's 23.8°C .The pressure remains constant at 1atm .Calculate the mass of the aluminum sample.
Chemistry
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer: The mass of aluminium sample is 55.4 gram

Explanation:

Q_{absorbed}=Q_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]      

where,

m_1 = mass of aluminium = ?

m_2 = mass of water = 300.0 g

T_{final} = final temperature = 23.8^0C

T_1 = temperature of aluminium = 94.5^oC

T_2 = temperature of water = 21.0^oC

c_1 = specific heat of aluminium = 0.897J/g^0C

c_2 = specific heat of water =  4.184J/g^0C

Now put all the given values in equation (1), we get

-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]

-[m_1\times 0.897\times (23.8-94.5)^0C]=[300.0g\times 4.184\times (23.8-21.0)]

m_1=55.4g

Therefore, the mass of aluminium sample is 55.4 gram

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