Question

An object is released from rest near a planet's surface. A graph of the acceleration as a

Answer 1

Answer:

The displacement and direction of the body after 2 seconds is 10 meters downwards

Explanation:

The given information are;

From the graph, the acceleration, is seen as the horizontal line that starts from the y-coordinate, y = -5 m/s²

Therefore;

The acceleration of the body after it was released from rest = -5 m/s² with an upward direction;

Which gives, the acceleration of the body downwards = Opposite sign to the acceleration of the body upwards = 5 m/s²

The displacement, s, of the body after 2 seconds is given by the following equation of motion;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the body = 0 m/s

t = The time duration of the displacement = 2 s

a = The acceleration of the body = 5 m/s², downwards

Therefore, by substituting the values, we have;

s = 0 × 2 + 1/2 × 5 × 2² = 10 meters

s = 10 meters

The displacement of the body after 2 seconds =  10 meters

Given that the direction of the displacement and the direction of the acceleration are the same, we have;

The displacement and direction of the body after 2 seconds = 10 meters downwards.