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3 years ago

An object is released from rest near a planet's surface. A graph of the acceleration as a

Physics

1 answer:

Reil [10]3 years ago

7 0

Answer:

The displacement and direction of the body after 2 seconds is 10 meters downwards

Explanation:

The given information are;

From the graph, the acceleration, is seen as the horizontal line that starts from the y-coordinate, y = -5 m/s²

Therefore;

The acceleration of the body after it was released from rest = -5 m/s² with an upward direction;

Which gives, the acceleration of the body downwards = Opposite sign to the acceleration of the body upwards = 5 m/s²

The displacement, s, of the body after 2 seconds is given by the following equation of motion;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the body = 0 m/s

t = The time duration of the displacement = 2 s

a = The acceleration of the body = 5 m/s², downwards

Therefore, by substituting the values, we have;

s = 0 × 2 + 1/2 × 5 × 2² = 10 meters

s = 10 meters

The displacement of the body after 2 seconds = 10 meters

Given that the direction of the displacement and the direction of the acceleration are the same, we have;

The displacement and direction of the body after 2 seconds = 10 meters downwards.

You might be interested in

A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical

Tanya [424]

Answer:

1 m = 39.37 in = 39.37/12 ft = 3.28 ft

V = 1145 k/hr = 1145k/hr * 6076 ft/k = 6957020 ft / hr

V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec

V = 1933 ft/sec / (3.28 ft / m) = 589 m/s

Check:

88 ft/sec = 60 mph

(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s

1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph

Also, 1318 / 1145 = 6076 / 5280 as it should

4 0

2 years ago

How far will a runner travel if she had an average speed of 10 km/hour and runs for 2.1 hours?

Rasek [7]

10 Km.
S= Speed
D= distance
T= time

S= d/t
but since you are solving for "d" the equation is d=st so you plug in 10 km/h for speed and 2.1 hours for time and just multiply them. The hours cancel out so you are left with 10km.

8 0

2 years ago

Read 2 more answers

if a person can jump maximum along distance of 3m ,on the earth how far could be jump on the moon where acceleration due to grav

allochka39001 [22]

Answer:

The person can jump 48 m on the Moon

Explanation:

The question parameters are;

The maximum long jump distance of a person on Earth, $R_{max}$ = 3 m

The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth

The distance the person can jump on the Moon is given as follows;

A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile

The horizontal range, $R_{max}$ , of a projectile motion is found by using the following formula

$R_{max} = \dfrac{u^2}{g}$

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

$R_{max} = 3 \, m = \dfrac{u^2}{9.8 \, m/s^2 }$

u² = 3 m × 9.8 m/s² = 29.4 m²/s²

Therefore, on the Moon, we have;

The acceleration due to gravity on the Moon, $g_{Moon}$ = 1/16 × g

∴ $g_{Moon}$ = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²

$R_{max \ Moon} = \dfrac{u^2}{g_{Moon}} = \dfrac{29.4 \ m^2/s^2}{0.6125 \, m/s^2 } \approx 48 \, m$

The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is $R_{max \ Moon}$ ≈ 48 m

8 0

2 years ago

An unusual fog that is denser than air begins to fill a room. Should the people in the room walk out or crwl out? The people sho

horsena [70]

Walk out. If it's denser than air, it'll settle to the bottom

8 0

2 years ago

This list shows the heights in feet of the 30 tallest mountains in the United States. 14,269 14,361 14,470 14,831 16,237 14,270

antoniya [11.8K]

Answer: a. Frequency. 20, 4, 3, 1, 1, 0, 1

Explanation:

Interval(Height in feet) - - - - - - - - frequency

14000 - 14999 - - - - - - - - - - - - - - - 20

15000 - 15999 - - - - - - - - - - - - - - - 4

16000 - 16999 - - - - - - - - - - - - - - - 3

17000 - 17999 - - - - - - - - - - - - - - - 1

18000 - 18999 - - - - - - - - - - - - - - - 1

19000 - 19999 - - - - - - - - - - - - - - - 0

20000 - 20999 - - - - - - - - - - - - - - 1

Frequency : (20, 4, 3 1, 1, 0, 1)

8 0

3 years ago