Zlz is an interger and -4

Will give Brainliest!!! PLEASE HELP!!! 30 Points for this

Vladimir [108]

Answer:

congruent and perpendicular

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The area of a bulletin board is 55 ft2. The length is nine feet less than four times the width. Find the length and the width, i

galben [10]

Answer:

The length and width are 11ft and 5ft respectively

Step-by-step explanation:

let the

length = L

Width = W

Area = LW = 55

The length is nine feet less than four times the width

L = 4W - 9

W (4W - 9) = 55

4W^2 - 9W -55 = 0

4W^2 - 20W + 11W - 55 = 0

4W(W - 5) + 11(W - 5) = 0

(W - 5)(4W + 11) = 0

W - 5 = 0 , 4W + 11=0

W = 5 or - 11/4

since the width cannot be negative, W = 5

LW = 55

L = 55/5

L = 11

The length and width are 11ft and 5ft respectively.

7 0

3 years ago

What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? Enter the equation in the box.

antiseptic1488 [7]

Check the picture below. So the parabola looks more or less like so.

let's recall that the vertex is half-way between the focus point and the directrix, at "p" units away from both.

Let's notice that the focus point is below the directrix, that means the parabola is vertical, namely the squared variable is the "x", and it also means that it's opening downwards as you see in the picture, namely that "p" is negative, in this case "p" is 1 unit, and thus is -1.

$\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5$