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Kipish [7]
4 years ago
15

Zlz is an interger and -4

Mathematics
1 answer:
kupik [55]4 years ago
6 0
Yes -4 is a interference number
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Jacob is a teacher. He made 75 cookies to give to his students on the first day of school. He gave 2 cookies to each student who
Lisa [10]

Answer:

See explanation

Step-by-step explanation:

Jacob has 75 cookies.

He gave 2 cookies to each student.

Complete the table:

\begin{array}{cc}\text{Number of student arrived}&\text{Number of cookies left}\\1&75-2=73\\2&73-2=71\\3&71-2=69\\...&...\end{array}

Let n be the number of students. After nth student arrived Jacob had left

g(n)=75-2n

cookies.

This is an arithmetic sequence with

g_1=g(1)=73\\ \\d=-2

Thus,

g_{n}=g_{n-1}-2\\ \\g(n)=g(n-1)-2

3 0
3 years ago
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What is 2+2*56*89/5+69
Natalija [7]

Answer:

2064.6 is the answer

Step-by-step explanation:

3 0
3 years ago
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Find the length of segment AB
SSSSS [86.1K]

Answer:

35

hope this helps you!!

6 0
3 years ago
My sister needs help!
Lunna [17]
Idk if she's too young to learn cross multiply, but this is an easier method.

Multiply everything by 4 which cancels out the 4 on the left side.
36z-16/5 <= 7z + 2
Now multiply everything by 5, cancelling out the right side 5.
36z-16 <= 35z + 10
Solve the equation normally
z-16<=10

z<=36
3 0
3 years ago
A sample of 66 obese adults was put on a low-carb diet for a year. The average weight loss was 11 pounds and the standard deviat
Illusion [34]

Answer:

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{19}{\sqrt{66}} = 6.02

The lower end of the interval is the sample mean subtracted by M. So it is 11 - 6.02 = 3.98 pounds

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

7 0
3 years ago
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