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3 years ago

Which statement is LEAST accurate regarding deviance and conformity?

Physics

2 answers:

frozen [14]3 years ago

7 0

Answer:

B.) the primary factor that determines if a behavior is deviant is the act itself

Explanation:

Social norms consists of behaviors that are considered acceptable. Any behavior that deviates from the social norms is a violation of social norms.

An act that is unacceptable by social norms is considered a deviance. An act does not have any intrinsic value to it. What is a good or bad act is defined by society.

Social norms vary form region to region. For example, in Tibet people greet each other by sticking out their tongues. This however would be considered a deviance in another country.

Social norms are not rules that are written down so this can cause confusion in a society.

guajiro [1.7K]3 years ago

4 0

The correct is option B

B) The primary factor that determines if a behavior is deviant is the act itself

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A busy waitress slides a plate of apple pie along a counter to a hungry customer sitting near the

Ostrovityanka [42]

Answer:

a. 0.5307 sec

b. 0.4458 m

c. = $v_x=0.84\ m/s\ ,\ v_y=5.2\ m/s$

Explanation:

Horizontal Motion

It describes the dynamics of an object thrown horizontally in free air. The initial horizontal velocity is maintained all the time since no horizontal forces are acting. The initial vertical velocity is zero at launch time, but it grows downwards powered by the acceleration of gravity.

The object hits the ground at a distance x from the point of launching, after having traveled a vertical distance $y_o$ , taking a time t to complete the travel. The formulas who relate the different magnitudes are

$v_x=v_o$

The horizontal velocity $v_x$ is the same regardless of the elapsed time

$v_y=gt$

$x=v_ot$

$\displaystyle y=y_o-\frac{gt^2}{2}$

The plate of apple pie left the counter at a speed

$v_o=0.84\ m/s$

The counter is $y_o=1.38\ m$ high.

Knowing that

$y_o=1.38\ m$

We use this formula to compute t

$\displaystyle y=y_o-\frac{gt^2}{2}$

At the moment when the plate hits the floor y=0

$\displaystyle 0=y_o-\frac{gt^2}{2}$

$\displaystyle y_o=\frac{gt^2}{2}$

Solving for t

$\displaystyle t=\sqrt{\frac{2y_o}{g}}$

$\displaystyle t=\sqrt{\frac{2(1.38)}{9.8}}$

$t=0.5307\ sec$

$x=(0.84)(0.5307)$

$x=0.4458\ m$

$v_x=0.84\ m/s$

$v_y=(9.8)(0.5307)$

$v_y=5.2\ m/s$

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Which stage of sleep usually comes before REM sleep

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4 years ago

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A pilot drops a package from a plane flying horizontally at a constant speed. Neglecting air resistance, when the package hits t

Dovator [93]

Answer:

The location of helicopter is behind the packet.

Explanation:

As the packet also have same horizontal velocity as same as the helicopter, and also it has some vertical velocity as it hits the ground.

The horizontal velocity remains same as there is no force in the horizontal direction. The vertical velocity goes on increasing as acceleration due to gravity acts.

So, the helicopter is behind the packet.

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3 years ago

What is the speed of the fastest baseball pitch ever thrown?

Annette [7]

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3 years ago

The cabinet is mounted on coasters and has a mass of 45 kg. The casters are locked to prevent the tires from rotating. The coeff

stira [4]

Answer:

the force P required for impending motion is 132.3 N

the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

Explanation:

Given that:

mass of the cabinet m = 45 kg

coefficient of static friction μ = 0.30

A free flow body diagram illustrating what the question represents is attached in the file below;

The given condition from the question let us realize that ; the casters are locked to prevent the tires from rotating.

Thus; considering the forces along the vertical axis ; we have :

$\sum f_y =0$

The upward force and the downward force is :

$N_A+N_B = mg$

where;

$\mathbf { N_A \ and \ N_B}$ are the normal contact force at center point A and B respectively .

$N_A+N_B = 45*9.8$

$N_A+N_B = 441$ ------- equation (1)

Considering the forces on the horizontal axis:

$\sum f_x = 0$

$F_A +F_B = P$

where ;

$\mathbf{ F_A \ and \ F_B }$ are the static friction at center point A and B respectively.

which can be written also as:

$\mu_s N_A + \mu_s N_B = P$

$\mu_s( N_A + N_B) = P$

replacing our value from equation (1)

P = 0.30 ( 441)

P = 132.3 N

Thus; the force P required for impending motion is 132.3 N

b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm

the largest value of "h" allowed for the cabinet is not to tip over is calculated by determining the limiting condition of the unbalanced torque whose effect is canceled by the normal reaction at $N_A$ and it is shifted to $N_B$ :

Then:

$\sum M _B = 0$

$P*h = mg*0.24$

$h =\frac{45*9.8*0.24}{132.3}$

h = 0.8 m

Thus; the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

6 0

3 years ago