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r-ruslan [8.4K]
3 years ago
8

Which statement is LEAST accurate regarding deviance and conformity?

Physics
2 answers:
frozen [14]3 years ago
7 0

Answer:

B.) the primary factor that determines if a behavior is deviant is the act itself

Explanation:

Social norms consists of behaviors that are considered acceptable. Any behavior that deviates from the social norms is a violation of social norms.

An act that is unacceptable by social norms is considered a deviance. An act does not have any intrinsic value to it. What is a good or bad act is defined by society.

Social norms vary form region to region. For example, in Tibet people greet each other by sticking out their tongues. This however would be considered  a deviance in another country.

Social norms are not rules that are written down so this can cause confusion in a society.

guajiro [1.7K]3 years ago
4 0
<span>The correct is option B
</span><span>
</span><span>B) The primary factor that determines if a behavior is deviant is the act itself</span>
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A ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s. What will the horizontal sp
gulaghasi [49]

Answer:

C

Explanation:

horizintal speed stays same

only vertical speed changes

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6 0
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Two long, parallel wires are separated by a distance of 2.60 cm. The force per unit length that each wire exerts on the other is
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Answer:

<em>10.75 A</em>

<em>The current is in opposite direction since it causes a repulsion force between the wires</em>

Explanation:

Force per unit length on the wires = 4.30×10^−5 N/m

distance between wires = 2.6 cm = 0.026 m

current through one wire = 0.52 A

current on the other wire = ?

Recall that the force per unit length of two wires conducting and lying parallel and close to each other is given as

F/l = \frac{u_{0}I_{1} I_{2}  }{2\pi r }

where F/l is the force per unit length on the wires

u_{0} = permeability of vacuum = 4π × 10^−7 T-m/A

I_{1} = current on the first wire = 0.520 A

I_{2} = current on the other wire = ?

r = the distance between the two wire = 0.026 m

substituting the value into the equation, we have

4.30×10^−5 = \frac{4\pi *10^{-7}*0.520*I_{2}  }{2\pi *0.026} =  \frac{ 2*10^{-7}*0.520*I_{2}  }{0.026}

4.30×10^−5 = 4 x 10^-6 I_{2}

I_{2} = (4.30×10^-5)/(4 x 10^-6) = <em>10.75 A</em>

<em>The current is in opposite direction since it causes a repulsion force between the wires.</em>

6 0
4 years ago
The pressure at the bottom of a lake is 300 000 N/m2 more than at the surface of the lake. The lake is fresh water (density = 10
MakcuM [25]

Answer:

h = 30.61 m

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In this problem they indicate the pressure at the bottom of the lake and the density of the water, for which they must ask what is the depth of the lake.

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The gauge pressure value is P- P_{atm} = 3 105 N / m²

          h = \frac{P - P_{atm}}{ \rho \ g}

let's calculate

          h = \frac{3 \ 10^5}{1000 \ 9.8}

          h = 30.61 m

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