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3 years ago

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In the photo below, astronaut Alan Bean works at the Apollo 12 lander. Describe the horizon and the surface you see. What kind o

f terrain did they land on for this, the second human Moon landing, and why ?

1 answer:

Marianna [84]3 years ago

3 0

Answer:

moon

Explanation:

I dont KNow

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A simple pendulum consists of a 2 kg bob attached to a 1.5 m long string. How much time (in s) is required for this pendulum to

Charra [1.4K]

Answer:

6.15 s

Explanation:

The period of a simple pendulum is given by the equation

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

For the pendulum in this problem,

L = 1.5 m (length)

$g=9.8 m/s^2$ (acceleration due to gravity on Earth)

Therefore, its period is

$T=2\pi \sqrt{\frac{1.5}{9.8}}=2.46 s$

And therefore, the time taken for the pendulum to complete 2.5 oscillations is equal to 2.5 times the period:

$t=2.5T=(2.5)(2.46)=6.15 s$

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3 years ago

I need help please...

Natalka [10]

No cluuuueee :/ sowwwwyyy but good luck

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3 years ago

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Imagine a raindrop starting from rest in a cloud 2 km in the air. If it fell with no air friction at all, it would accelerate to

LenKa [72]

Answer:

2) 433 mph

Explanation:

The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:

$v^2 = u^2 + 2ad$

where

v is the final velocity

u = 0 is the initial velocity (the raindrop starts from rest)

a = g = 9.8 m/s^2 is the acceleration due to gravity

d = 2 km = 2000 m is the distance covered

Solving for v,

$v=\sqrt{u^2 +2gd}=\sqrt{0^2+2(9.8 m/s^2)(2000)}=198 m/s$

And keeping in mind that

1 mile = 1609 metres

1 hour = 3600 s

The speed converted into miles per hour is

$v=198 \frac{m}{s}\cdot \frac{3600 s/h}{1609 m/mi}=433 mph$

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3 years ago

A car is traveling at 114 m/s and changes its velocity to 77 m/s in 9 sec.

suter [353]

Answer:

<u>Given</u><u> </u><u>-</u>

Initial Velocity, u = 114 m/s
Final velocity, v = 77 m/s.
Time taken, t = 9 sec.

<u>To</u><u> </u><u>find</u><u> </u><u>-</u><u> </u>

Acceleration of the car.

<u>Solu</u><u>tion</u><u> </u><u>-</u>

Here, using the equation of motion v = u + at we can find the acceleration easily.

★ Here,

V = Final velocity
U = Initial Velocity
A = Acceleration
T = Time.

<u>Subs</u><u>tituting</u><u> </u><u>the</u><u> </u><u>values</u><u> </u><u>-</u>

→ 77 = 114 + a(9)

→ 9a = 114 - 77

→ 9a = 37

→ a = 37/9

→ a = 4.1 m/s

<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>accele</u><u>ration</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>car</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>4</u><u>.</u><u>1</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>

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I'll give you branliest- A student uses a counting technique to estimate time. She counts "one one-thousand, two one-thousand, t

Scrat [10]

<h2><em>the correct answer is </em></h2><h2><em>A) 111.36 seconds</em></h2><h2><em>HOPE IT HELPS (◕‿◕✿) </em></h2>

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