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never [62]
3 years ago
11

Chemoautotrophs use ___ as an energy source and ___ as a carbon source. select one:

Chemistry
2 answers:
vitfil [10]3 years ago
6 0

autotrophs are organisms that can synthesise organic compounds (e.g.: carbohydrates) from inorganic C compounds (e.g.: CO2)

Phototrophs are those use photons also known as light energy, chemotrophs are those who utilize chemical energy as their source of energy. chemotrophs can either use inorganic or organic molecules as source of energy. from the options given there are 2 answers with CO2, the correct combination is CO2 with inorganic compounds

Therefore chemoautotrophs use inorganic compounds as an energy source and CO2 as a carbon source

Agata [3.3K]3 years ago
3 0
The answer is E.
Chemoautotrophs are organisms that use inorganic <span>compounds as an energy source and CO2 as a carbon source. The organisms live in </span>hostile environments like dark depths of the sea. Inorganic energy sources that they use are mostly hydrogen sulfide, elemental sulfur, ferrous iron, molecular hydrogen, and ammonia. 
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Read 2 more answers
Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the followi
marta [7]

Answer : The value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

Explanation :

The following equilibrium reactions are :

(1) 2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2 K_1=5.40\times 10^{-16}

(2) 2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l) K_2=1.06\times 10^{10}

(3) CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g) K_3=2.68\times 10^{-9}

The final equilibrium reaction is :

CO_2(g)\rightleftharpoons C(s)+O_2(g) K_{goal}=?

Now we have to calculate the value of K_{goal} for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

K_{goal}=\sqrt{K_1\times K_2\times K_3}

Now put all the given values in this expression, we get :

K_{goal}=\sqrt{(5.40\times 10^{-16})\times (1.06\times 10^{10})\times (2.68\times 10^{-9})}

K_{goal}=1.238\times 10^{-7}

Therefore, the value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

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3 years ago
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nikitadnepr [17]

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