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never [62]
3 years ago
11

Chemoautotrophs use ___ as an energy source and ___ as a carbon source. select one:

Chemistry
2 answers:
vitfil [10]3 years ago
6 0

autotrophs are organisms that can synthesise organic compounds (e.g.: carbohydrates) from inorganic C compounds (e.g.: CO2)

Phototrophs are those use photons also known as light energy, chemotrophs are those who utilize chemical energy as their source of energy. chemotrophs can either use inorganic or organic molecules as source of energy. from the options given there are 2 answers with CO2, the correct combination is CO2 with inorganic compounds

Therefore chemoautotrophs use inorganic compounds as an energy source and CO2 as a carbon source

Agata [3.3K]3 years ago
3 0
The answer is E.
Chemoautotrophs are organisms that use inorganic <span>compounds as an energy source and CO2 as a carbon source. The organisms live in </span>hostile environments like dark depths of the sea. Inorganic energy sources that they use are mostly hydrogen sulfide, elemental sulfur, ferrous iron, molecular hydrogen, and ammonia. 
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5 0
3 years ago
Describe the steps to balancing a chemical equation.
scZoUnD [109]
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If possible, start with an element found in one compound on each side of the equation. Change the coefficients (the numbers in front of the compound or molecule) so that the number of atoms of the element is the same on each side of the equation. Remember, to balance an equation, you change the coefficients, not the subscripts in the formulas.

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6 0
4 years ago
What are the different ions that acids contain?
fgiga [73]
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6 0
3 years ago
Which corresponds to a pressure of 1.23 atm??
Vadim26 [7]

Atmospheric pressure<span>, sometimes also called barometric pressure, is the pressure exerted by the weight of air in the </span>atmosphere of Earth<span> (or that of another planet)</span>

1 atm is equivalent to = 101325 Pa

= 760 mmHg

= 760 torr

= 1.01325 bar

So 1.23 atm is equal to

= 124629.8 Pa

= 934.8 mmHg

= 934.8 torr

<span>= 1.2462 bar</span>

6 0
3 years ago
Help me please! I don't understand how to do this.
Whitepunk [10]

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3 years ago
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