Answer: 4.12
Explanation:
we know that the given mol is 8.23 mol and they are 2NaI and I2 so we will write the equation like this.
8.23mol NaI x 1mol of I2 ÷ 2molNaI = 4.115≅ 4.12 mol of I2
we placed NaI at the bottom to cancel out with the 8.23 mol of NaI
Answer:
<em><u>The answer is</u></em>: <u>False.</u>
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Explanation:
Six Sigma is a methodology for continuous improvement that increases performance by controlling variability and focusing the process on customer specifications. It will be used within other methods such as Rummler: Brache, Scrum and TQM.
JumpStart is an educational media franchise for children, consisting mainly of educational games, produced by JumpStart Games.
<em><u>The answer is</u></em>: <u>False.</u>
<h3>
Answer:</h3>
43.27 g Mg
<h3>
Explanation:</h3>
The balanced equation for the reaction between magnesium metal and hydrochloric acid is;
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
From the equation;
1 mole of magnesium reacts with 2 moles of HCl
We are given;
3.56 moles of Mg and 3.56 moles of HCl
Using the mole ratio;
3.56 moles of Mg would react with 7.12 moles of HCl, and
3.56 moles of HCl would react with 1.78 moles of Mg
Therefore;
The amount of magnesium was in excess;
Moles of Mg left = 3.56 moles - 1.78 moles
= 1.78 moles
But; 1 mole of Mg = 24.305 g/mol
Therefore;
Mass of magnesium left = 1.78 moles × 24.305 g/mol
= 43.2629 g
= 43.27 g
Thus, the mass of magnesium that remained after the reaction is 43.27 g
Answer:
b. 4.4
Explanation:
pH is related to the concentration of H₃O⁺ through the following equation:
pH = -log([H₃O⁺]) = -log(4 x 10⁻⁵)
pH = 4.4
