The amount of water that the girls on the

Mathematics

2 answers:

hram777 [196]3 years ago

6 0

For those of you who are doin the test rn here are the answers to all of them. Hope this helps! ;) I did the quiz

SashulF [63]3 years ago

4 0

Answer:

Its 45 oz less than i just took the test and got it right

Step-by-step explanation:

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Please help me solve and you'll get a brainlist

jasenka [17]

Y=4x+1
Let y=0
0=4x+1
4x=-1
x=-1/4

Let x=0
Y=4*0+1
Y=0+1
Y=1

Therefore, the ordered pair is (-1/4, 1)

4 0

2 years ago

Please help me answer number 4! And if you can, please explain!

Leno4ka [110]

If Nathan does 9 minutes of push ups for 3 days, that's 9 divided by 3, which is 3. (9/3=3) So nathan does 3 minutes of push ups each day, so just multiply each day by 3 to find the correlation between the two.

The Table should look like this:

# of days # of Minutes
1 3
2 6
3 9
4 12
5 15
6 18
7 21

5 0

2 years ago

The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to

Firdavs [7]

Rewrite the boundary lines y = -1 - x and y = x - 1 as functions of y :

y = -1 - x ==> x = -1 - y

y = x - 1 ==> x = 1 + y

So if we let x range between these two lines, we need to let y vary between the point where these lines intersect, and the line y = 1.

This means the area is given by the integral,

$\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy$

The integral with respect to x is trivial:

$\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy$

For the remaining integral, integrate term-by-term to get

$\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}$

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line y = 1 and (0, -1)), so its area is 1/2*4*2 = 4.