Question

Calculate the average travel time for each distance, and then use the results to calculate.

Answer 1

The average time that it takes for the car to travel the first 0.25m is 2.23 s

The average time that it takes for the car to travel the first 0.25 m is given by:

$t=\frac{2.24 s+2.21 s+2.23 s}{3}=2.227 s \sim 2.23 s$

The average time to travel just between 0.25 m and 0.50 m is 0.90 s

First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:

$t_1 = 3.16 s - 2.24 s=0.92 s\\t_2 = 3.08 s- 2.21 s=0.87 s\\t_3 =3.15 s- 2.23 s=0.92 s$

Then, the average time can be calculated as

$t=\frac{0.92 s+0.87 s+0.92 s}{3}=0.90 s$

Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s

The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):

$v=\frac{d}{t}=\frac{0.25 m}{0.90 s}=0.28 m/s$

Answer 2

Answer:

The average time that it takes for the car to travel the first 0.25m is  

2.23  s.

The average time to travel just between 0.25 m and 0.50 m is  

0.90  s.

Given the time taken to travel the second 0.25 m section, the velocity would be  

0.28  m/s.

Explanation:

Just did this problem! :)