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3 years ago

A student stands on a scale, and the scale reads 85 N. What is being measured by the scale

Physics

1 answer:

Dmitry [639]3 years ago

5 0

Force. Force is measured by newtons, probably because he came up with the equations to calculate force.

Hope this helps!

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What is velocity? why is it important?

Setler [38]

Answer:

Velocity is the rate at which the position changes

Velocity is the rate at which the position changesWhy do we need

Velocity is the rate at which the position changesWhy do we needVectors make it convenient to handle quantities going in different directions.. 

Explanation:

Thank you!

5 0

2 years ago

Read 2 more answers

The coordinates of a bird flying in the xy-plane are given by x(t)=αt and y(t)=3.0m−βt2, where α=2.4m/s and β=1.2m/s2.part a:Cal

8090 [49]

Α $=2.4 \frac{m}{s}$

β $=1.2 \frac{m}{s^2}$

$x(t)=at$

$y(t)=3-$ β $t^2$

$Vx(t)=$ α

$Vy(t)=-2$ β $t$

$vectorV=[$ α $;-2$ β $t]$

$ax(t)=0$

$ay(t)=-2$ β $t$

$vector a [0;-2$ β $t]$

3 0

3 years ago

Brandon buys a new Seadoo. He goes 22 km north from the beach. He then goes 11km to the east. Then chases a boat 3 km north. Wha

KIM [24]

Answer:

36kms

Explanation:

22+1=33

33+3=36

6 0

3 years ago

Juan is receiving bills from the hospital even though his insurance company said his procedure would be covered in full. What st

BaLLatris [955]

==> Jot down notes before and after making each call, and avoid calling during business hours when people are busy.

==> Save all emails and bills, and follow up to make sure people did what they said they would do.

5 0

3 years ago

A 0.500-V potential difference is maintained across a 1.50-m length of tungsten wire that has a cross-sectional area of 0.800 mm

Genrish500 [490]

Answer:

5.95 A

Explanation:

From the question

R = ρL/A..................... Equation 1

Where R = resistance of the tungsten wire, ρ = Resistivity of the tungsten wire, L = length, A = cross sectional area.

Given: L = 1.5 m, A = 0.8 mm² = 0.8×10⁻⁶ m, ρ = 5.60×10⁻⁸ Ω.m

Substitute these values into equation 1

R = 1.5(5.60×10⁻⁸)/0.8×10⁻⁶

R = 0.084 Ω.

Finally, using Ohm law,

V = IR

Where V = Voltage, I = current

Make I the subject of the equation

I = V/R............... Equation 2

I = 0.5/0.084

I = 5.95 A

4 0

3 years ago