Answer:
0.0231 m/s
Explanation:
Given the question :
A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. What is his average velocity?
Distance walked south = 2.099 metre
Time taken = 29.01s
Distance walked north = 1.429 metre
Average Velocity = Displacement / time
The Displacement is hence,
(2.099 m - 1.429m) = 0.67m
Average Velocity = 0.67m / 29.01s
Average Velocity = 0.02309 m/s
Average Velocity = 0.0231 m/s
Explanation:
We have,
According to attached figure, the height of the inclined plane is 60 m and force acting on the block is 10 N. It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :
W = mgh
or
Hence, the correct option is (A) "600 J".
Answer:
the net force on the object is 6 N.
Explanation:
Given;
force applied to the right on the object, = 16 N
force applied to the left of the object, = 16 N
force applied downward on the object, = 6 N
The net horizontal force on the object =
The net vertical force on the object =
The net force on the object is calculated as;
Therefore, the net force on the object is 6 N.
Explanation:
The given data is as follows.
q = -25.0 kJ, Pressure (P) = 1.50 atm
= (12 - 6) L = 6 L
Therefore, product of pressure and change in volume will be as follows.
= 7.5 L atm
=
= 759.75 J
Now, we will calculate the change in internal energy as follows.
=
= -25000 kJ + 759.75 J
= 24240.25 J
or, = 24.240 kJ (as 1 kJ = 1000 J)
Thus, we can conclude that the change in internal energy () for a system is 24.240 kJ.