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3 years ago

The part of the atom with a positive charge is the ________.

Physics

2 answers:

NemiM [27]3 years ago

6 0

Answer:

protons

Explanation:

mixer [17]3 years ago

3 0

Answer:

excited

Explanation:

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I need help with question 8 and 9

Wewaii [24]

8) The height of the shelf is 2.04 m

9) The gravitational potential energy is 100 J

Explanation:

The gravitational potential energy of an object is given by:

$PE=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object, relative to the ground

For the object in this problem, we have

m = 10 kg

$g=9.8 m/s^2$

And we know that

PE = 200 J

Therefore we can re-arrange the formula to solve for h, the heigth of the object:

$h=\frac{PE}{mg}=\frac{200}{(10)(9.8)}=2.04 m$

As before, the gravitational potential energy of the object is given by:

$PE=mgh$

where in this case, we have:

m = 10 kg is the mass of the object

h = 2.04 m is the height of the object from the ground

While in this case, the acceleration of gravity on this planet is

$g=4.9 m/s^2$

Substituting,

$PE=(10)(4.9)(2.04)=100 J$

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0

3 years ago

An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first

GarryVolchara [31]

Answer:

The right answer is "1.369 m/s²".

Explanation:

The given values are:

Distance (s)

= 260 m

Initial speed (u)

= 26 m/s

Reaction time (t')

= 0.51 s

During reaction time, the distance travelled by locomotive will be:

⇒ $s'=ut'$

$=26\times 0.51$

$=13.26 \ m$

Remained distance between locomotive and car:

⇒ $x=s-s'$

$=260-13.26$

$=246.74 \ m$

Now,

The final velocity to avoid collection is, V = 0 m/s

From third equation of motion:

⇒ $V^2=u^2+2ax$

On putting the estimated values, we get

⇒ $0=(26)^2+2\times a\times 246.74$

⇒ $0=676+493.48a$

⇒ $493.48a=-676$

⇒ $a=-\frac{676}{493.48}$

⇒ $a=1.369 \ m/s^2$

3 0

3 years ago

A substance has a vapor pressure of 77.86 mm Hg at 318.3 K and a vapor pressure of161.3 mmHg at 340. 7 K. Calculate its heat of

zavuch27 [327]

Explanation:

It is given that,

Initial vapor pressure, P₁ = 77.86 mm

Initial temperature, T₁ = 318.3 K

Final vapor pressure, P₂ = 161.3 mm

Initial temperature, T₂ = 340.7 K

We need to find its heat of vaporization. It can be calculated by using Clausius-Clapeyron equation.

$ln(\dfrac{P_2}{P_1})=\dfrac{\Delta_{vap}H}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})$

$\Delta _{vap} H=\dfrac{R\ ln(\dfrac{P_2}{P_1})}{(\dfrac{1}{T_1}-\dfrac{1}{T_2})}$

$\Delta _{vap} H=\dfrac{0.008 314\ ln(\dfrac{161.3}{77.86})}{(\dfrac{1}{318.3}-\dfrac{1}{340.7})}$

$\Delta _{vap} H=29.31\ kJ/mol$

So, the heat of vaporization of a substance is 29.31 kJ/mol. Hence, this is the required solution.

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3 years ago

How to treat thyroid at home

saul85 [17]

Answer:

<h2>Thyroid is common cold which is treated at home , You should consult to a doctor ....</h2>

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