k = 5.29
a = 0.78m/s²
KE = 0.0765J
<u>Explanation:</u>
Given-
Mass of air tracker, m = 1.15kg
Force, F = 0.9N
distance, x = 0.17m
(a) Effective spring constant, k = ?
Force = kx
0.9 = k X0.17
k = 5.29
(b) Maximum acceleration, m = ?
We know,
Force = ma
0.9N = 1.15 X a
a = 0.78 m/s²
c) kinetic energy, KE of the glider at x = 0.00 m.
The work done as the glider was moved = Average force * distance
This work is converted into kinetic energy when the block is released. The maximum kinetic energy occurs when the glider has moved 0.17m back to position x = 0
As the glider is moved 0.17m, the average force = ½ * (0 + 0.9)
Work = Kinetic energy
KE = 0.450 * 0.17
KE = 0.0765J
Answer:
The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Explanation:
Given;
number of turns of the flat circular loop, N = 18 turns
radius of the loop, R = 15.0 cm = 0.15 m
current through the wire, I = 0.51 A
The magnetic field through the center of the loop is given by;
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Answer:
a)
b)
Explanation:
The gravitational force on the satellite is calculated with Newton's Gravitation Law:
Where 
is Earth's mass, 
is the satellite mass, 
is the distance between their centers, where 
is the height of the satellite (from Earth's surface) and 
is Earth's radius, and 
is the gravitational constant.
a) With these values we then have:
b) And the fraction this force is of the satellite’s weight <em>W=mg</em> is:
The volume of the cylindrical can is given by:
V = πr²h
V = volume, r = base radius, h = height
Differentiate both sides of the equation with respect to time t. The radius r doesn't change over time, so we treat it as a constant:
dV/dt = πr²(dh/dt)
Given values:
dV/dt = -527in³/min
r = 8in
Plug in and solve for dh/dt:
-527 = π(8)²(dh/dt)
dh/dt = -2.62in/min
The height of the water is decreasing at a rate of 2.62in/min
