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Montano1993 [528]
3 years ago
14

X-√6 is a factor of x°4-36​

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

  • (x² - 6)(x² + 6)

Step-by-step explanation:

Nope, x-√6 is a factor of x^4-36. Let solve the question by factorization method.

x^4 - (√6)^4

x^4 - (√6)^4

(x²)² - (√6²)^²

(x²)² - (√6²)^²

(x² - 6)(x² + 6)

Hence, the required factor forms of equation is (x² - 6)(x² + 6)

Therefore, x-√6 is not a factor of x^4-36.

<u>Formula used while solving the problem :</u>

1. a² - b² = (a + b) (a - b)

2. a^4 - b^4 = ( a² + b²)(a² - b²)

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Step-by-step explanation:

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Which of the following is the solution to the differential equation dP/dt+P=10 with the initial condition P(0)=4
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  •    Option C.    P=10-6e^{-t}

Explanation:

<u>1. Separate variables:</u>

      \dfrac{dP}{dt}+P=10\\ \\ \\ \\\dfrac{dP}{dt}=-P+10\\ \\ \\ \dfrac{dP}{-P+10}=dt

<u></u>

<u>2. Find the indefinite integrals</u>

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<u></u>

<u>3. Solve for P</u>

      10-P=e^{-t+C}\\ \\ 10-P=Ke^{-t}\\ \\ P=10-Ke^{-t}

<u></u>

<u>4. Use the initial condition, P(0) = 4, to find K:</u>

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<u></u>

<u>5. Substitute K = 6 into the integrated equation:</u>

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