Q is a concave mirror.
Explanation:
The image formed by a concave mirror is observed to be virtual, erect and larger than the object.
Given: Height h = 6 ft or the vertical component "y" this become the initial height, therefore if you want to know the total height of the stone with respect to the ground. you can just add up the two value below.
Initial Velocity Vi = 41 ft/s g = -32.2 ft/s² acting downward
Require: Height h = ?
Formula: y = Vf² - Vi²/2g
y = 0 - (41 ft/s)²/2(-32.2 ft/s²)
y = -1,681 ft²/s²/(-64.4 ft/s²)
y = 26.10 ft
Answer:
F t = m Δv impulse delivered = change in momentum
Δv = 100 * .1 / .5 = 20 m/s original speed of puck
KE = 1/2 m v^2 = .5 * 20^2 / 2 = 100 J initial KE of puck
E = μ m g d energy lost by puck
Ff = μ m g = m a deceleration of puck due to friction
a = μ g = 9.8 * .2 = 1.96 m/s^2
v2 = a t + v1 = -1.96 * 4 + 20 = 12.2 m/s speed of puck on striking box
m v2 = M V conservation of momentum when puck strikes box
V = m v2 / M = 12.2 * .5 / .8 = 7.63 m/s speed of box after collision
KE = 1/2 M V^2 = .8 * 7.63^2 / 2 = 23.3 J KE of box after collision
KE = μ M g d energy lost by box in sliding distance d
d = 23.3 / (.3 * .8 * 9.8) = 9.91 m distance box slides
Answer:
According to the National Cancer Institute, the average cost of a pack of cigarettes is $6.28, which means a pack-a-day habit sets you back $188 per month or $2,292 per year. 1 Ten years of smoking comes with a $22,920 price tag
Explanation:
I hope this helps
The question is incomplete. The complete question is :
In your job as a mechanical engineer you are designing a flywheel and clutch-plate system. Disk A is made of a lighter material than disk B, and the moment of inertia of disk A about the shaft is one-third that of disk B. The moment of inertia of the shaft is negligible. With the clutch disconnected, A is brought up to an angular speed ?0; B is initially at rest. The accelerating torque is then removed from A, and A is coupled to B. (Ignore bearing friction.) The design specifications allow for a maximum of 2300 J of thermal energy to be developed when the connection is made. What can be the maximum value of the original kinetic energy of disk A so as not to exceed the maximum allowed value of the thermal energy?
Solution :
Let M.I. of disk A = 
So, M.I. of disk B = 
Angular velocity of A = 
So the kinetic energy of the disk A = 
After coupling, the angular velocity of both the disks will be equal to ω.
Angular momentum will be conserved.
So,
Now,
Therefore, the maximum initial K.E. = 3066.67 J
