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Ilya [14]
4 years ago
15

What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a perio

d of exactly 24.0 hours (86,400 seconds). (Measurement is from the center of Earth.)
Physics
2 answers:
ziro4ka [17]4 years ago
8 0
What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a period of exactly 24.0 hours (86,400 seconds). (Measurement is from the center of Earth.) A. 6.5 × 10^4 m B. 3.8 × 10^5 m C. 4.2 × 10^7 m D. 9.5 × 10^7 m
kolbaska11 [484]4 years ago
4 0

Answer:

42400 km

Explanation:

The time taken by a satellite to complete one revolution around the earth is called the time period of the satellite.

The time period for the satellite is given by

T = \frac{2\pi }{R}\times \sqrt{\frac{(R+h)^{3}}{g}}

where, R be the radius of earth, h be the height of satellite from earth's surface and g be the acceleration due to gravity.

Substitute, 86400 s for T, 6400000 m for R and 9.8 m/s^2 for g , we get

86400 = \frac{2\pi }{6400000}\times \sqrt{\frac{(6400000+h)^{3}}{9.8}}

h = 35954355.13 m

h = 36 x 10^3 km

Distance from the centre of earth is R + h = 6400 km + 36000 km = 42400 km .

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nydimaria [60]

Answer:

A bicycle.

Explanation:

A compound machine is a machine consisting of multiple simple machines.

A bicycle contains 3 simple machines. A lever, pulley, and wheel-and-axle.

all other choices are simple machines.

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7 0
3 years ago
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A person can jump 1.5m on the earth. How high could the person jump on a planet having the twice the mass of the earth and twice
MrMuchimi
F=mg=Gm1m2/r^2
g=Gm2/r^2
g=2Gm2/(2r)^2=2Gm2/4r^2=Gm2/2r^2
So since there is half times the gravity on this unknown planet that has twice earth's mass and twice it's radius, then the person can jump twice as high. 1.5*2= 3m high

5 0
4 years ago
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A car travels in a straight line with an average velocity of 80 km/h for 2.5 h and then with an average velocity of 40 km/h for
maks197457 [2]

Answer:

260 km

65 km/hr

Explanation:

The displacement of an object is the distance moved by that object in a particular direction.

velocity = displacement / time, therefore,

Displacement = velocity * time.

Total displacement for the 4 HR trip = displacement for 2.5 hr + displacement for 1.5 hr

total displacement = (80 * 2.5) + (40 * 1.5)

Total displacement = 200 + 60

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average velocity = 260 km/ 4 hr

average velocity = 65 km/hr

7 0
3 years ago
Two balls are kicked with the same initial speeds. Ball A was kicked at the angle 20° above horizontal and ball B was kicked at
GREYUIT [131]

Answer:

Ball A

Explanation:

Let the initial speed of the balls be u .

Angle of projection for ball A = 20°

Angle of projection for ball B = 75°

As we know that at highest point, the ball has only horizontal speed which always remains constant throughout the motion because the acceleration in horizontal direction is zero.

Speed of ball A at highest point = u Cos 20° = 0.94 u

Speed of ball B at highest point = u Cos 75° = 0.26 u

So, the ball A has bigger speed than B.

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3 years ago
Heat energy moves:_______.
steposvetlana [31]

c) only from warmer areas to colder areas.

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3 0
3 years ago
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