Answer
given,
mass of baseball(m) = 144 g = 0.144 Kg
initial velocity(u) = 29 m/s
mass of brick(M) = 5.25 Kg
speed of the brick (v') = 1.32
speed of base ball after collision = ?
using conservation of momentum
m u = m v + Mv'
0.144 x 29 = 0.144 v + 5.25 x 1.32
0.144 v = -2.754
v = -19.125 m/s
b) KE before collision
KE_i = 60.55 J
KE after collision
KE_f = 30.91 J
Answer: 4 over 3
Explanation:
well x^3=64/27
take cube roots for both sides
x= 3√64/27
Use property of radical expressions and you’ll have the answer.
x=4/3
Answer:
2452.5 N/m^2
Explanation:
given:
density =500kg/m^3
viscosity = 10 Pa-s
diameter of tube= 2 m
and L be length
since gravity is the only force shear force will balance it
so we can write
mg=
A=
m=
therefore
putting values we get
calculating we get 2452.5 N/m^2
Answer: v = 20 m/s
Explanation: Solution:
Use the formula of Kinetic Energy and derive for v:
KE = 1/2 mv²
To find v:
v = √ 2 KE / m
= √ 2 ( 100000 J ) / 500 kg
= √ 400 m/s
= 20 m/s