Explanation:
It is given that,
Electric field experienced by an electron, ![E=1200\ N/C](https://tex.z-dn.net/?f=E%3D1200%5C%20N%2FC)
Charge on electron, ![q=-1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D-1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
Mass of electron, ![m=9.1\times 10^{-31}\ C](https://tex.z-dn.net/?f=m%3D9.1%5Ctimes%2010%5E%7B-31%7D%5C%20C)
The electric force is balanced by the force acting on electron as,
ma = qE
![a=\dfrac{qE}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BqE%7D%7Bm%7D)
![a=\dfrac{-1.6\times 10^{-19}\times 1200}{9.1\times 10^{-31}}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B-1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%201200%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D)
![a=-2.1\times 10^{14}\ m/s^2](https://tex.z-dn.net/?f=a%3D-2.1%5Ctimes%2010%5E%7B14%7D%5C%20m%2Fs%5E2)
So, the acceleration of the electron is
. As the electron is a negatively charged particle, the field lines is from negative to positive charge.
Answer:
![894.12\ \text{N}](https://tex.z-dn.net/?f=894.12%5C%20%5Ctext%7BN%7D)
![284.013\ \text{J}](https://tex.z-dn.net/?f=284.013%5C%20%5Ctext%7BJ%7D)
Explanation:
U = Energy = 76 J
x = Displacement of spring = 0.17 m
k = Spring constant
Energy is given by
![U=\dfrac{1}{2}kx^2\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 76}{0.17^2}\\\Rightarrow k=5259.51\ \text{Nm}](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7Dkx%5E2%5C%5C%5CRightarrow%20k%3D%5Cdfrac%7B2U%7D%7Bx%5E2%7D%5C%5C%5CRightarrow%20k%3D%5Cdfrac%7B2%5Ctimes%2076%7D%7B0.17%5E2%7D%5C%5C%5CRightarrow%20k%3D5259.51%5C%20%5Ctext%7BNm%7D)
Force is given by
![F=kx\\\Rightarrow F=5259.51\times 0.17\\\Rightarrow F=894.12\ \text{N}](https://tex.z-dn.net/?f=F%3Dkx%5C%5C%5CRightarrow%20F%3D5259.51%5Ctimes%200.17%5C%5C%5CRightarrow%20F%3D894.12%5C%20%5Ctext%7BN%7D)
The magnitude of force must you apply to hold the platform is
.
Now ![x=0.17+0.2=0.37\ \text{m}](https://tex.z-dn.net/?f=x%3D0.17%2B0.2%3D0.37%5C%20%5Ctext%7Bm%7D)
![U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 5259.51\times 0.37^2\\\Rightarrow U=360.013\ \text{J}](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7Dkx%5E2%5C%5C%5CRightarrow%20U%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%205259.51%5Ctimes%200.37%5E2%5C%5C%5CRightarrow%20U%3D360.013%5C%20%5Ctext%7BJ%7D)
Additional energy
![360.013-76=284.013\ \text{J}](https://tex.z-dn.net/?f=360.013-76%3D284.013%5C%20%5Ctext%7BJ%7D)
Answer:
C.) Gravity
Explanation:
The projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile.
Answer:
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Explanation: