Answer:
C.
Explanation:
The electronic configuration of N (7 electrons): 1s² 2s² 2p³.
The orbital 1s is filled with two electrons and their spinning direction is opposite and also electrons of 2s.
3p contains (3 electrons) should fill the 3 orbitals firstly. Every orbital contains 1 electron and be in the same spin direction.
So, the right choice is c.
A is wrong because 2 electrons of 3p are paired in the first orbital before filling every orbital.
B is wrong because the 2 electrons of 1s and 2s are in the same direction and also 2 electrons of 3p are paired in the first orbital before filling every orbital.
D is also wrong the 2 electrons of 1s and 2s are in the same direction and the electron in the second orbital of 3p are in opposite direction of the other 2 electrons.
The answer is A. As the first statement is a true statement. Hope this help you
Answer:
The concentration of NaOH solution is 3,65M
Explanation:
The neutralization of NaOH with HCl is:
NaOH + HCl → NaCl + H₂O
You are titrating 12,67 mL HCl 2,74M with your NaOH solution, the moles of HCl in the beaker are:
12,67 mL ≡ 0,01267L×
= <em>0,0347 moles HCl </em>≡ 0,0347 moles NaOH
The volume that you require for total neutralization of 12,67 mL HCl 2,74M is:
13,65 mL - 4,50 mL = <em>9,50 mL </em>≡ 0,0095L
Thus, the concentration of NaOH solution is:
= <em>3,65M</em>
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I hope it helps!
<u>Given:</u>
Volume of 0.9% NaCl = 500 ml
Time (t) = 4 hrs
<u>To determine:</u>
The infusion rate of NaCl in ml/hr
<u>Explanation:</u>
Based on the information- 500 ml of NaCl is to be given over a time span of 4 hrs
Hence, the volume of NaCl to be administered per hr is:-
= 1 hr * 500 ml/4 hr = 125 ml
Ans: Infusion rate = 125 ml/hr
Answer:
The first option
Explanation:
Carbon is a p-block element. It is the 6th element on the periodic table and therefore it has 6 electrons.
The sub-level notation is given as:
1s² 2s² 2p²
The s-sublevel can only accommodate two maximum electrons because it has one orbital. This is why both 1s and 2s contains just two electrons each. When both sub-levels are filled, we have just 2 remaining electrons to fill the p-sublevel.
The p-sublevel contains 3 orbitals and can accommodate a maximum of 6 electrons. But we have just 2 electrons. According to Hund's rule of maximum mulitiplicity, electrons will go into degenerate orbitals singly before paring up. Therefore, the first two orbitals in p-sublevel will receive an electron each.
This is why the first model fits.
