Answer and Explanation:
It is not necessary to know the amount of salt in the aqua, because we know that the presence of salt in the water will increase its density.
In this case, salt increases the mass of the water, without increasing the volume of water. as the egg will not change in volume or water, we know that the density of the egg will be constant, while the change in the mass of the water with the addition of salt, will change the density of the water which will increase progressively until it becomes denser than the egg and, consequently, it will not let the egg sink.
N(H₂O)=1g÷18g/mol=0,055mol
N(H₂O)=0,055mol · 6·10²³ 1/mol (Avogadro number)= 3,33·10²² molecules.
Answer:
Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]
Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]
Explanation:
An amphoteric substance as HSO₃⁻ is a substance that act as either an acid or a base. When acid:
HSO₃⁻(aq) + H₂O(l) ⇄ H₃O⁺(aq) + SO₃²⁻(aq)
And Ka, the acid dissociation constant is:
<h3>Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]</h3><h3 />
When base:
HSO₃⁻(aq) + H₂O(l) ⇄ OH⁻(aq) + H₂SO₃(aq)
And kb, base dissociation constant is:
<h3>Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]</h3>
Answer:
Bromine (Br) loses an electron, so it is the reducing agent.
Explanation:
A reducing agent also called a reducer, is known to be an electron donor. A reducing agent is oxidized, because it loses electrons in the redox reaction.
A oxidising agent also called a oxidant or oxidiser, is known to be an electron acceptor. A oxidising agent is reduced, because it gains electrons in the redox reaction.
Cl2(aq) + 2Br-(aq) --> 2Cl-(aq) + Br2(aq)
Half ionic equations,
Cl2(aq) + 2e- --> 2Cl-(aq)
2Br-(aq) --> Br2(aq) + 2e-
Reducing agent = Br-
Oxidizing agent = Cl2
