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4vir4ik [10]
3 years ago
14

pls help !!! A line passes through the point (0,-4) and has a slope of 3/2. what is the equation of the line ?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
3 0
An equation of a line can be written as :
y=mx+p

where m is the slope. So we can say that m=\frac32  .
To fine the value of p , we use the coordinates of the point  (0,-4). Can you find the value of p ? 
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The length of a rectangle is 8 inches more than the width. the perimeter is 44 inches. find the length and width of the rectangl
vazorg [7]

Answer: Width is 7 inches, length is 15 inches.

Step-by-step explanation:

Let the width be w. Then, the length is w+8.

2(w+w+8)=44\\\\w+w+8=22\\\\2w+8=22\\\\2w=14\\\\w=7\\\\\implies l=15

8 0
2 years ago
2-7 please help BRAINLEST
Temka [501]

Answer:

y = 40

Step-by-step explanation:

  __y_  x  8      = 8 x 5

       8

y = 40

4 0
4 years ago
Read 2 more answers
gretchen and Ezia received equal scores on a test made up of multiple choice questions and an essay. Gretchen got 18 multiple ch
timurjin [86]
The multiply choice were worth 4 points. 
Gretchen= 18x+19
Ezia= 15x+31

So basically you can enter any number. At first I picked 3 and then I did the math and I got 73 points for Gretchen and 76 points for Ezia. 

Then I pick four and then I got 91 points for them both. This is how I got the answer: 

18x+19=15x+31
18(4)+19=15(4)+31
72+19=60+31
91=91
5 0
4 years ago
Read 2 more answers
The perimeter of a rectangular painting is 326 cm. if the width of the painting is 74 cm, what is the length?
True [87]
Perimeter (P) = 326 cm

Width (w) = 74 cm

Length (l) = ?

We know,

P = 2* (l + w)

326 = 2 (l + 74)

l + 74 = 163

l = 89 

Hence, length is 89 cm.
7 0
4 years ago
Write a quadratic function for each graph described.
user100 [1]

Answer:

y=2x^2-\frac{4}{3}x-\frac{10}{3}

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

so

we can write the equation of the parabola as

y=a(x+1)(x-\frac{5}{3})

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

40=a(5+1)(5-\frac{5}{3})

40=a(6)(\frac{10}{3})

40=20a\\a=2

substitute

y=2(x+1)(x-\frac{5}{3})

apply distributive property

y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}

see the attached figure to better understand the problem

6 0
3 years ago
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