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Maru [420]
3 years ago
15

Help please science kids

Physics
1 answer:
IceJOKER [234]3 years ago
6 0
It helps because it's being transported blah blah whatever the last person said when you first asked this question
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A car travels due east 14 miles in 18 minutes. Then, the car turns around and returns to its starting point, taking an additiona
N76 [4]

Answer:

(a) The average speed is 0.85 milles/minute

(b) The average velocity is zero

Explanation:

In order to answer part (a) and (b) you have to apply the formulas for average speed and average velocity which are:

<em>-Average speed formula:</em>

v=\frac{d}{t}

where d is the total distance traveled and t is the tota time

Replacing the given values:

v=\frac{14+14}{18+15}\\v=\frac{28}{33} \\v=0.85 milles/minute

Notice that you have to replace the total distance, which is 14 milles for the go plus 14 milles for the return. The same for the total time.

<em>-Average velocity formula:</em>

V = Δx/Δt

Where V is the velocity vector, Δx is the displacement and Δt is the change in time

V= \frac{X2-X1}{t2-t1}

Where X2 is the final position and X1 is the initial position

In this case X1= 0 i and X2=0 i (i is the unit vector in the x direction). So, the displacement is zero.

Therefore, the average velocity is:

V= 0 i [milles/minute]

4 0
3 years ago
You are In-line skates at the top of a small hill. Your potential energy is equal to 1000 J. The last time we checked, your mass
stira [4]

A) <u>Weight = mass × acceleration (due to gravity)  </u>

= 60×9.8  

= 588 N  

<u>B) Potential energy = mass x gravity x change in height </u>

1,000 = 60.0 x 9.8 x h

h =  1.7 m      

<u>C) Kinetic energyF = potential energyI </u>

KEF = 1/2mv2  

PEI = mgh = 1,000 J

1/2mv2 = 1,000

1/2(60.0)v2 = 1,000  

v2 = 33.33

v = 5.77 m/s

3 0
4 years ago
How many significant digits are measurement 0.00210 mg?
jek_recluse [69]
There are 3 significant figures, if that answers the question.
8 0
3 years ago
Read 2 more answers
Velocity of B rays ?<br>​
stich3 [128]

Answer:

is from 9 x 107 m/sec to 27 x 107 m/s

6 0
3 years ago
Read 2 more answers
A spring stretches 3.5 cm when a 9 g object is hung from it. The object is replaced with a block of mass 26 g which oscillates i
evablogger [386]

Answer:

The period of motion  of new mass T = 0.637 sec

Explanation:

Given data

Mass of object (m) = 9 gm = 0.009 kg

Δx = 3.5 cm = 0.035 m

We know that spring force is given by

F = m g

F = 0.009 × 9.81 = 0.08829 N

Spring constant

k = \frac{F}{x}

k = \frac{0.08829}{0.035}

k = 2.522 \frac{N}{m}

New mass(m_1) = 26 gm = 0.026 kg

Now the period of motion is given by

T = 2 \pi \sqrt{\frac{m}{k} }

T = 2 \pi \sqrt{\frac{0.026}{2.522} }

T = 0.637 sec

This is the period of motion  of new mass.

3 0
3 years ago
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