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lana [24]
3 years ago
13

Why is there an upward force on objects in water?

Physics
2 answers:
ludmilkaskok [199]3 years ago
6 0
From pressure, so if you had a pot and turned it upside down and put it in water then turned it on its side the air bubbles would come out but if you kept trying to push it down it would get harder just like an inflatable boat if u turned it upside down tried to pull it under water you couldnt because of the pressure hope this helps can u mark brainliest please
prisoha [69]3 years ago
3 0
This is due to water pressure
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The expanding gases that leave the muzzle of a rifle also contribute to the recoil. A .30 caliber bullet has mass 7.20×10−3 kg a
katen-ka-za [31]

Answer:

Mg= 1.3418 kg*m/s

Explanation:

Mass of rifle

m_{r}=2.90 kg

Recoil velocity of rifle

v_{r}=1.95 m/s

Momentum of rifle

m*v_{r}=3.0kg*1.95\frac{m}{s}==5.85 \frac{kg*m}{s}

mass of bullet

mb=7.2x10^{-3} kg=0.0072 kg

velocity of bullet relative to muzzel

v_{b} = 601 m/s

velocity of bullet relative to earth= 601 - 1.95=599.05 m/s

momentum of bullet

m_{b}*m_{b}=7.2x10^{-3}kg*599.05\frac{m}{s}=4.3132 \frac{kg*m}{s}

the momentum of the propellant gases = momentum of rifle - momentum of bullet

the momentum of the propellant gases

Mg=5.655 -4.3132

Mg= 1.3418 kg*m/s

the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle is 1.3418 kgm/s

5 0
3 years ago
Two weight lifters (Herb and Foley) wonder which one is doing the most work. Which statement is true?
Luda [366]

The solution would be like this for this specific problem:

 

Work = 50kg * 1.5m

= 75

Work = 55kg * 1 m

=55

 

75 > 55

Therefore, the statement that is true is “Herb lifting 50 kg 1.5 meters does more work than Foley lifting 55 kg 1 meter.”

3 0
4 years ago
Read 2 more answers
Which of the following is a metal?<br> Calcium (Ca)<br> Iron (Fe)<br> Sodium (Na)<br> all of these
scoundrel [369]
Your answer is D.) all of these.
4 0
4 years ago
An object with a weight of 20 kg will move _______ an object with a weight of 20 g if the same amount of force is placed on the
elena55 [62]
The answer should be D

7 0
3 years ago
An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 61.0 cm mark on the track. The glider compl
Novosadov [1.4K]

Answer:

T = 2.82 seconds.

The frequency \mathbf{f = 0.36 \ Hz}

Amplitude A = 25.5 cm

The maximum speed of the glider is \mathbf{v = 56.87 \ rad/s}

Explanation:

Given that:

the time taken for 11 oscillations is 31 seconds ;

SO, the time taken for one oscillation is :

T = \frac{31}{11}

T = 2.82 seconds.

The formula for calculating frequency can be expressed as :

f = \frac{1}{T}

f = \frac{1}{2.82}

\mathbf{f = 0.36 \ Hz}

The amplitude is determined by using the formula:

A = \frac{d}{2}

The limits that the spring makes the oscillations are from 10 cm to 61 cm.

The distance of the glider is, d = (61 - 10 )cm = 51 cm

Replacing 51 for d in the above equation

A = \frac{51}{2}

A = 25.5 cm

The maximum speed of the glider is:

v = A \omega

where ;

\omega = \frac{2 \pi}{T}

\omega = \frac{2 \pi}{2.82}

\omega = 2.23 \ rad/s

v = A \omega

v = 25.5 *2.23

\mathbf{v = 56.87 \ rad/s}

3 0
3 years ago
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