Answer:
50.8 watt
Explanation:
we know that P=W÷t
W=F.S S-->distance=50 ft= 15.24 m
F=ma
=100×10=1000 N
SO W= 1000×15.24
=15240 J
NOW
P=W÷t t=5 mints = 5×60=300 sec
P=15240÷300
P=50.8 watt
Answer:
pagtalon?
Explanation:
because that had to be the answer
Answer:
KE = 2.535 x 10⁷ Joules
Explanation:
given,
angular speed of the fly wheel = 940 rad/s
mass of the cylinder = 630 Kg
radius = 1.35 m
KE of flywheel = ?
moment of inertia of the cylinder
![I = \dfrac{1}{2}mr^2](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7B1%7D%7B2%7Dmr%5E2)
=![\dfrac{1}{2}\times 630\times 1.35^2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20630%5Ctimes%201.35%5E2)
= 574 kg m²
kinetic energy of the fly wheel
![KE = \dfrac{1}{2}I\omega^2](https://tex.z-dn.net/?f=KE%20%3D%20%5Cdfrac%7B1%7D%7B2%7DI%5Comega%5E2)
KE = 2.535 x 10⁷ Joules
the kinetic energy of the flywheel is equal to KE = 2.535 x 10⁷ Joules
One is bigger than the other and they are the same shape
Answer: The minimum acceleration for the air plane is 2.269m/s2.
Explanation: To solve such problem the equation of motion are applicable.
The initial velocity is 0 since the airplane was initially standing. We are going to use this equation
V^2=U^2+2as
33^2=0+2a (240)
a= 2.269m/s2