Which of the following is an example of an alloy?

giving the incomplete equation 2N2O5 (g) which set of products completes and balances the incomplete equarion

a_sh-v [17]

Answer:

The complete question is as follows

Given the incomplete equation: 2 N2O5(g) ==> Which set of products completes and balances the incomplete equation?

A)2 N2(g) + 3 H2(g)

B)2 N2(g) + 2 O2(g)

C)4 NO2(g) + O2(g)

D)4 NO(g) + SO2(g)

The correct option is C) 4NO2(g) + O2(g)

Explanation:

Note that the products should be NO2 and O2 since the reactant is entirely made up of N and O. option A is not correct as hydrogen cannot emerge as a product in this reaction. Matter can never be created or be destroyed bu can only change in a chemical reaction. Option D is not also correct for the same reason.

Option B is not correct since it did not balance the number of atoms of O and N in the reactant side of the equation.

The option C) 4NO2(g) + O2(g) is therefore the right option since it balances both the elements and the number of atoms of the elements present.

7 0

3 years ago

Insulators prevent the loss of heat. A company is designing a mug that will keep coffee warm for a long time. Which one of these

Mumz [18]

Rubber, because it doesn’t conduct heat and it is a good insulator

3 0

2 years ago

If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressu

mixas84 [53]

Answer:

The answer to your question is V2 = 29.6 l

Explanation:

Data

Pressure 1 = P1 = 12 atm

Volume 1 = V1 = 23 l

Temperature 1 = T1 = 200 °K

Pressure 2 = 14 atm

Volume 2 = V2 = =

Temperature 2 = T2 = 300°K

Process

1.- To solve this problem use the Combine gas law.

P1V1/T1 = P2V2/T2

-Solve for V2

V2 = P1V1T2 / T1P2

2.- Substitution

V2 = (12)(23)(300) / (200)(14)

3.- Simplification

V2 = 82800 / 2800

4.- Result

V2 = 29.6 l

5 0

3 years ago

The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

ololo11 [35]

The allowable combination for the atomic orbital is n=3, l=1 or 2, $m_{l}$ =+1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; $m_{l}$ values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of $m_{l}$ = +1, the l value must be higher than 0. Two l values are consistent with n and $m_{l)$ values:

l= 1 or 2

Therefore, the allowable condition is n=7, l=1 or 2, $m_{l}$ =+3.

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

7 0

1 year ago

1 pts.what is the charge on the hydrogen end of a water molecule?

Savatey [412]

Positive

And Negative for oxygen.

4 0

3 years ago