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34kurt
2 years ago
5

A stone with a mass of 0.70 kg is attached to one end of a string 0.70 m long. The string will break if its tension exceeds 65.0

N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed.
Physics
1 answer:
mixas84 [53]2 years ago
4 0

Answer:v=8.06 m/s

Explanation:

Given

mass of stone m=0.7 kg

length of string L=0.7 m

Maximum Tension T=65 N

the string will not break if Centripetal Force is less than maximum tension

T=\frac{mv^2}{r}

65=\frac{0.7\times v^2}{0.7}

v^2=65

v=\sqrt{65}

v=8.06 m/s

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3 years ago
Provide descriptions and examples of the following forces: friction, gravity and elastic.
arsen [322]

Answer:

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EG:-

A coaster sliding against a table.

Gravity:-

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5 0
3 years ago
A wheel initially has an angular velocity of 18 rad/s, but it is slowing at a constant rate of 2 rad/s 2 . By the time it stops,
ZanzabumX [31]

Answer:

5) 13 revolutions (approximately)

Explanation:

We apply the equations of circular motion uniformly accelerated :

ωf²= ω₀² + 2α*θ Formula (1)

Where:

θ : angle that the body has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed  ( rad/s)

Data:

ω₀ = 18 rad/s

ωf = 0

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Revolutions calculation that turns the wheel until it stops

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8 0
3 years ago
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