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34kurt
2 years ago
5

A stone with a mass of 0.70 kg is attached to one end of a string 0.70 m long. The string will break if its tension exceeds 65.0

N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed.
Physics
1 answer:
mixas84 [53]2 years ago
4 0

Answer:v=8.06 m/s

Explanation:

Given

mass of stone m=0.7 kg

length of string L=0.7 m

Maximum Tension T=65 N

the string will not break if Centripetal Force is less than maximum tension

T=\frac{mv^2}{r}

65=\frac{0.7\times v^2}{0.7}

v^2=65

v=\sqrt{65}

v=8.06 m/s

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