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3 years ago

According to the nebular theory, what early event eventually led to the formation of our solar system?

1 answer:

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Answer:Solar system formed about 4.6 billion year ago, when gravity pulled together low-density cloud of interstellar gas and dust (called a nebula)(movie). The Orion Nebula, an interstellar cloud in which star systems and possibly planets are forming. Initially the cloud was about several light years across.

Explanation:

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The rate an object is moving relative to a reference point is its

natulia [17]

Velocity is an object's rate of change (usually over time) of its displacement.

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3 years ago

A 415-kg container of food and water is dropped from an airplane at an altitude of 300m. First, consider the situation ignoring

frozen [14]

1) 7.8 s

Ignoring air resistance, the only force acting on the container is gravity. Therefore, we can use the following suvat equation for the free-fall case:

$s=ut+\frac{1}{2}at^2$

where

s = 300 m is the displacement of the container

u = 0 is the initial vertical velocity of the container, which starts from rest

a = g = 9.8 m/s^2 is the acceleration of gravity

t is the time

Here we have chosen downward as positive direction, so all quantities are positive

Solving the equation for t, we find:

$s=\frac{1}{2}gt^2\\t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(300)}{9.8}}=7.8 s$

2) 76.4 m/s

The speed of the container at any time t can be found by using another suvat equation:

$v=u+at$

where

v is the speed at time t

u = 0 is the initial speed

a = g = 9.8 m/s^2 is the acceleration of gravity

t is the time

Substituting t = 7.8 s, the time of flight, we can immediately find the final speed of the container, just before hitting the ground:

$v=0+(9.8)(7.8)=76.4 m/s$

3) 4067 N

In this case, there is a parachute that produces a drag force acting upward.

When the container is falling at constant speed, 6 m/s down, it means that its acceleration is zero, so the net force acting on it is zero. This means that the air drag balances the weight of the container, therefore we can write:

$F=mg$

where

F is the air drag

m is the mass of the container

g is the acceleration of gravity

Substituting m = 415 kg, we find the magnitude of the drag force:

$F=(415)(9.8)=4067 N$

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4 years ago

A ball is thrown up into the air. When it falls back down and reaches the

bezimeni [28]

Answer:

A. 3.3 m

Explanation:

Here, we have to use conservation of energy principle.

When the ball is at maximum height, the instantaneous velocity at that point is 0 m/s. So, the kinetic energy of the ball is also 0 at the maximum height. Thus, at maximum height, the energy possessed by the ball is gravitational potential energy only.

Now, when the ball reaches the ground, all the gravitational potential energy changes into kinetic energy because of the conservation of energy.

Therefore, the energy transformation can be given as:

Decrease in potential energy = Increase in Kinetic energy

Decrease in potential energy is given as:

$\Delta U=mg(h-0)=mgh$