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zavuch27 [327]
3 years ago
8

Two boats start together and race across a 62-km-wide lake and back. Boat A goes across at 62 km/h and returns at 62 km/h. Boat

B goes across at 31 km/h, and its crew, realizing how far behind it is getting, returns at 93 km/h. Turnaround times are negligible, and the boat that completes the round trip first wins. (a) Which boat wins
Physics
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

boat A

Explanation:

Distance to one point of the race = 62 km

Speed of boat A across the distance = 62 km/h

Speed of boat A to return the same distance = 62 km/h

Time = Distance / Speed

Time taken by boat A to cover the first length

\text{Time}=\frac{62}{62}=1\ hour

Time taken by boat A to cover the return length

\text{Time}=\frac{62}{62}=1\ hour

So, total time taken by boat A is 1+1 = 2 hours

Speed of boat B across the distance = 31 km/h

Speed of boat B to return the same distance = 93 km/h

Time = Distance / Speed

Time taken by boat A to cover the first length

\text{Time}=\frac{62}{31}=2\ hour

Time taken by boat A to cover the return length

\text{Time}=\frac{62}{93}=0.67\ hour

So, total time taken by boat B is 2+0.67 = 2.67 hours

Hence boat A wins.

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answer

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explanation

as we know frequency is equal to 1 /t

f= 457 Hz

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SO, 1/457

=0.0022sev

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A nurse pushes a cart by exerting a force on the handle at a downward angle of 36 degrees below the horizontal. the loaded cart
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Since it was stated that it must move at constant velocity, so the only force it must overpower is the frictional force.

So the equation is:

F cos θ = Ff

F cos 36 = 65 N

F = 80.34 N

 

<span>So the nurse must exert 80.34 N of force</span>

4 0
3 years ago
A tortoise and a hare are having a 1,000-meter race. The tortolse runs the
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Explanation:

6 0
3 years ago
A piece of wood is floating in a bathtub. A second piece of wood sits on top of the first piece, and does not touch the water. I
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the water level remains same

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6 0
3 years ago
Clay Matthews, a linebacker for the Green Bay Packers, can reach a speed of 10.0 m/s. At the start of a play, Matthews runs down
MA_775_DIABLO [31]

Answer:

a)   D_ total = 18.54 m,   b)        v = 6.55 m / s

Explanation:

In this exercise we must find the displacement of the player.

a) Let's start with the initial displacement, d = 8 m at a 45º angle, use trigonometry to find the components

           sin 45 = y₁ / d

           cos 45 = x₁ / d

           y₁ = d sin 45

           x₁ = d sin 45

           y₁ = 8 sin 45 = 5,657 m

           x₁ = 8 cos 45 = 5,657 m

The second offset is d₂ = 12m at 90 of the 50 yard

            y₂ = 12 m

            x₂ = 0

total displacement

          y_total = y₁ + y₂

          y_total = 5,657 + 12

          y_total = 17,657 m

          x_total = x₁ + x₂

          x_total = 5,657 + 0

          x_total = 5,657 m

          D_total =   17.657 i^+ 5.657 j^  m

          D_total = Ra (17.657 2 + 5.657 2)

          D_ total = 18.54 m

b) the average speed is requested, which is the offset carried out in the time used

           v = Δx /Δt

the distance traveled using the pythagorean theorem is

         r = √ (d1² + d2²)

          r = √ (8² + 12²)

          r = 14.42 m

The time used for this shredding is

         t = t1 + t2

         t = 1 + 1.2

         t = 2.2 s

let's calculate the average speed

         v = 14.42 / 2.2

         v = 6.55 m / s

8 0
3 years ago
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