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zavuch27 [327]
3 years ago
8

Two boats start together and race across a 62-km-wide lake and back. Boat A goes across at 62 km/h and returns at 62 km/h. Boat

B goes across at 31 km/h, and its crew, realizing how far behind it is getting, returns at 93 km/h. Turnaround times are negligible, and the boat that completes the round trip first wins. (a) Which boat wins
Physics
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

boat A

Explanation:

Distance to one point of the race = 62 km

Speed of boat A across the distance = 62 km/h

Speed of boat A to return the same distance = 62 km/h

Time = Distance / Speed

Time taken by boat A to cover the first length

\text{Time}=\frac{62}{62}=1\ hour

Time taken by boat A to cover the return length

\text{Time}=\frac{62}{62}=1\ hour

So, total time taken by boat A is 1+1 = 2 hours

Speed of boat B across the distance = 31 km/h

Speed of boat B to return the same distance = 93 km/h

Time = Distance / Speed

Time taken by boat A to cover the first length

\text{Time}=\frac{62}{31}=2\ hour

Time taken by boat A to cover the return length

\text{Time}=\frac{62}{93}=0.67\ hour

So, total time taken by boat B is 2+0.67 = 2.67 hours

Hence boat A wins.

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A typical meteor that hits the earth's upper atmosphere has a mass of only 2.5 g, about the same as a penny, but it is moving at
attashe74 [19]

Answer:

Answer:u=66.67 m/s

Explanation:

Given

mass of meteor m=2.5 gm\approx 2.5\times 10^{-3} kg

velocity of meteor v=40km/s \approx 40000 m/s

Kinetic Energy of Meteor

K.E.=\frac{mv^2}{2}

K.E.=\frac{2.5\times 10^{-3}\times (4000)^2}{2}

K.E.=2\times 10^6 J

Kinetic Energy of Car

=\frac{1}{2}\times Mu^2

=\frac{1}{2}\times 900\times u^2

\frac{1}{2}\times 900\times u^2=2\times 10^6  

900\times u^2=4\times 10^6

u^2=\frac{4}{9}\times 10^4

u=\frac{2}{3}\times 10^2

u=66.67 m/s

8 0
3 years ago
An object has a mass of 30 grams and measures 3cmx2cmx1cm. What is the density of the object?
dimulka [17.4K]
The density of the object is the ratio of its mass and volume. From the given dimensions above, we determine the volume through the equation,

      V = L x W x H

Substituting,

    V = (3 cm)(2 cm)(1 cm) = 6 cm³

From the idea presented above,
    d = m/V

Substituting the known values,

   d = (30 g)/ (6 cm³) = 5 g/cm³

ANSWER: 5 g/cm³
4 0
3 years ago
A spatially challenged goldfish swims along the x-axis only. Its initial position is 7.8 m. After swimming back and forth a whil
Verdich [7]

Answer:

<em>The fish displacement was -3.4 m</em>

Explanation:

<u>Distance and Displacement</u>

A moving object constantly travels some distance at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

This sum is obtained independently of the direction the object moves.

The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.

The displacement, when the object moves in one axis only is given by:

d = final position - initial position

We know the fist started at 7.8 m from a given reference along the x-axis.

After some undisclosed movements, it ends up at the position 4.4 m. Thus, the displacement is:

d = 4.4 m - 7.8 m = -3.4 m

This means the fish ended up to the left of the position it started from.

The fish displacement was -3.4 m

3 0
3 years ago
How is momentum conserved in a newtons cradle <br><br> when one steel ball hits the other
arsen [322]

In Newton's Cradle experiment we know that all cradles of same mass and identical to each other

Now we know that when two identical objects collide elastically then they interchange their velocity

So here we have same illustration

When Newton pulls up a cradle and release it will move hit another cradle which is at rest

Due to elastic collision between them first cradle comes to rest and another cradle will move ahead with same speed this process remains the same and one by one all cradle hit another.

So at the last the cradle at the end will move off with the same speed as the first cradle will hit with the speed.

So in this experiment the cradle at the last end will move off at same distance away from the right end as that of left end we pull the cradle.

So here we can say that in horizontal direction when all cradles are colliding each other there is no external force on the system so momentum is conserved and they all will move off with same speed and hence we observe the above condition.

8 0
3 years ago
When two forces are acting a body in opposite direction their resultant become 6N and when they are acting in the same direction
Norma-Jean [14]

Answer:

9 and 3 N

Explanation:

Forces in the same direction sum up to produce the resultant force;

One force subtract the other will give the resultant force when they are in opposite directions;

Lets say one direction is forwards and the opposite backwards;

We have one force, let's say force A, in the forwards direction and another force, force B, acting in the same (forwards) or opposite (backwards) direction;

If B is acting in the same direction, then the resultant force (in this case) will be as follows:

A + B = 12

If B is acting in the opposite direction, then the resultant force will be as follows:
A - B = 6

Summing the two equations will allow us to solve for A:

A + B + (A - B) = 12 + 6

2A = 18

A = 9

Substitute this into either of the above equations and we can solve for B:
(9) - B = 6

B = 9 - 6

B = 3

5 0
2 years ago
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