2 years ago

How many atoms of phosphorus are in 9.20 mol of copper(II) phosphate?

1 answer:

4 0

The number of atoms of phosphorus in copper (II) phosphate [Cu3 (PO4)2] is determined by multiplying first 9.20 by 2 since there are two phosphorus atoms in the compound and multiplying again with Avogadro's number. The answer is 1.108 x 10^25 atoms.

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The concentration of NaOH is 25.00% by mass, it means that 25.00% of the mass of the solution is of NaOH. Hence:

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