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3 years ago

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Landon was taking a math test. He finished 1/2 of the test in 3/5 of an hour. How much of the test will he have done in one hour

if he keeps the same pace?

1 answer:

timama [110]3 years ago

7 0

Answer:

$\frac{5}{6}\ of\ the \ test$

Step-by-step explanation:

we know that

Landon finished 1/2 of the test in 3/5 of an hour

so

by proportion

Find out how much of the test will he have done in one hour

$\frac{(1/2)}{(3/5)}\frac{test}{hours} =\frac{x}{1}\frac{test}{hour}\\ \\x=(1/2)*(5/3)\\ \\x=\frac{5}{6}\ of\ the \ test$

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According to the article "Clemente's Impact Wanes in Puerto Rico 40 Years after His Death," what happens in Puerto Rico in 2012

zhannawk [14.2K]

Answer:

so this is math

Step-by-step explanation:

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3 years ago

Simplify the expression (x^19 y^21)^4/(x^2 y^6)^2<br><br> The simplified expression is ________.

Masja [62]

I got x^72y^72 i hope this helps

3 0

3 years ago

Read 2 more answers

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$

$A2=(4)(x)=4x\ in^2$

$A3=(x)(7)=7x\ in^2$

$A4=(4)(7)=28\ in^2$

The total area of the second rectangle is the sum of the four areas

$A=A1+A2+A3+A4$

State the product of (x+4) and (x+7) as a trinomial

$(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28$

Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?

we know that

The area of the second rectangle is equal to

$A=A1+A2+A3+A4$

For x=2 in

substitute the value of x in the area of each portion

$A1=(2)(2)=4\ in^2$

$A2=(4)(2)=8\ in^2$

$A3=(2)(7)=14\ in^2$

$A4=(4)(7)=28\ in^2$

$A=4+8+14+28$

$A=54\ in^2$

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

$A(x)=x^{2} +11x+28$

For x=2 in

substitute and solve for A(x)

$A(2)=2^{2} +11(2)+28$

$A(2)=4 +22+28$

$A(2)=54\ in^2$ ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0

4 years ago

From 1960 to 1980 , the consumer price index (cpi) increased from 29.6 to 82.4. If a frozen chicken pie cost $0.28 in 1960 and t

mojhsa [17]

CPI in 1960 = 29.6

CPI in 1980 = 82.4

Growth (%) in CPI = $\frac{\text{CPI in 1980 - CPI in 1960}}{\text{CPI in 1960}}$ × 100

⇒ Growth (%) in CPI = $\frac{82.4-29.6}{29.6}$ × 100

⇒ Growth (%) in CPI = 178.3783.. %

⇒ Growth (%) in CPI = 178.4%

Now, we know that price of frozen chicken pie in 1960 = $0.28

Also, we know that over 1960 to 1980, frozen chicken pie price grew at the same rate as CPI

Hence, Price of Chicken Pie in 1980 = Price of Chicken Pie in 1960 × (1 + Growth in CPI)

⇒ Price of Chicken Pie in 1980 = 0.28 × (1 + 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + (0.28 × 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.49952

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.50

⇒ Price of Chicken Pie in 1980 = $0.78

Hence, price of chicken pie in 1980 would be ~$0.78

8 0

3 years ago

Read 2 more answers

PLEASE HURRY. 55P WRONG ANSWERS GET REMOVED!!!!!!!

sertanlavr [38]

<em>Answer:</em>

<em>1172. 08 in²</em>

<em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>A(prism) = 2(lw + lh + wh) - Ab(cylinder)</em>

<em>= 2(16*11 + 16*11 + 11*11) - πr²</em>

<em>= 2(176 + 176 + 121) - 3.14*16</em>

<em>= 2*473 - 50.4</em>

<em>= 946 - 50.24</em>

<em>= 895.76 in²</em>

<em>A(cylinder) = πr² + 2πr*h</em>

<em>= 3.14*16 + 2*3.14*4*9</em>

<em>= 50.24 + 226.08</em>

<em>= 276.32 in²</em>

<em>A(total) = 895.76in² + 276.32in² = 1172.08 in²</em>

<em>Good luck !</em>

6 0

3 years ago