Answer:
a) [Tris0] : [Tris] = 1 : 100
b) Range = 7.1 to 9.1
Explanation:
a) Calculation of ratio of the basic and the acidic forms of tris
pH of a buffer is calculate using Henderson-Hasselbalch equation
Conjugate acid of Tris dissociated as
For tris,
Salt or Basic form = tris0
Acid or Acidic form = Tris
pKa = 8.1
pH = 6.1
[Tris0] : [Tris] = 1 : 100
b) Range of Tris
Range of any buffer is:
From (pKa -1) to (pKa+1)
So, range of Tris is:
From (8.1 - 1) to (8.1 +1)
or from 7.1 to 9.1
The dichotomous key is not given here, however, the correct dichotomous key is as follows:
step- 1a cell has a nucleus and organelles - go to step 2
1b cell has no nucleus or organelles - bacterial cell
step- 2a cell has a cell wall - go to step 3
2b cell has no cell wall - animal cell
step- 3a cell has chloroplasts - plant cell
3b cell has no chloroplasts - fungal cell
Using this dichotomous key the cell can be identified as - Fungal cell.
A dichotomous key is an essential scientific tool that is used to find out the various kinds of organisms on their observable traits. Dichotomous keys have a series of statements with two different choices in each step that will take the student or user to the correct identification.
Identification of the given cell:
1. Follow step 1.
- If cells have a nucleus and organelles - yes then go to step 2
2. follow step 2.
- 2a. if cell has a cell wall - yes go to step 3
3. follow step 3.
- 3a. if cell has chloroplasts - no then fungal cell
Fungal cells have a nucleus and cell organelles enclosed with a cell wall around the plasma membrane but do not have chloroplast.
Thus, Using this dichotomous key the cell can be identified as - Fungal cell.
Learn more about fungal cells:
brainly.com/question/14470940
Answer:
Empirical formula is CH₂O.
Molecular formula = C₆H₁₂O₆
Explanation:
Given data:
Mass of hydrogen = 3.36 g
Mass of carbon = 20.00 g
Mass of oxygen = 26.64 g
Molar mass of compound = 180.156 g/mol
Empirical formula = ?
Molecular formula = ?
Solution:
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number
Number of gram atoms of H = 3.36 / 1.01 = 3.3
Number of gram atoms of O = 26.64 / 16 = 1.7
Number of gram atoms of C = 20 / 12 = 1.7
Atomic ratio:
C : H : O
1.7/1.7 : 3.3/1.7 : 1.7/1.7
1 : 2 : 1
C : H : O = 1 : 2 : 1
Empirical formula is CH₂O.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = CH₂O = 12×1 + 2× + 16
Empirical formula mass = 30
n = 180.156 / 30
n = 6
Molecular formula = n (empirical formula)
Molecular formula = 6 (CH₂O)
Molecular formula = C₆H₁₂O₆
There are 2.06 x 10²⁴ atoms
<h3>Further explanation
</h3>
The mole is the number of particles (atoms, molecules, ions)contained in a substance
1 mol = 6.02.10²³ particles
Moles can also be determined from the amount of substance mass and its molar mass
