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Grace [21]
3 years ago
14

Which of the following is true for the reaction below? CO2(g) + 393.5 kJ C(s) + O2(g)

Chemistry
2 answers:
AleksandrR [38]3 years ago
6 0
It is endothermic and the ∆H = +393.5 kJ.
Solnce55 [7]3 years ago
5 0
Since energy is given to the reactant side, the reaction is endothermic reaction and it is given by ΔH = +393.5 kJ

Therefore option A is correct.
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Balance the following chemical equation <br> __Mg+__O2–&gt;__MgO
mario62 [17]

Answer:

2Mg^+ +O2 right arrow 2MgO

Explanation:

6 0
3 years ago
Read 2 more answers
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
Mixtures can be separated into their components by taking advantage of differences in the chemical properties of the components.
Sedaia [141]
The method of separating mixtures by means of their differences in the chemical properties of the components is less convenient because these methods requires reactions therefore needs energy, increasing the costs for the process.
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A dangerous example of diffusion?
KengaRu [80]
Adding water to acid that's kind of dangerous
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3 years ago
Do hydrogen lose 1 2 or 3 electrons to other atoms
iren2701 [21]

Answer:<em> Hydrogen can lose as much as possible there is no limits to it.</em>

<em>Hope this helps!</em>

<em>I am joyous to assist you anytime!</em>

<em>-Jarvis</em>

<em>Extras: Hydrogen is the chemical element with the symbol H and atomic number 1. hydrogen is the lightest element in the periodic table. Hydrogen is the most abundant chemical substance in the Universe (;</em>

7 0
3 years ago
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