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Anarel [89]
3 years ago
15

Which of these is not a property owner of a mineral

Chemistry
2 answers:
e-lub [12.9K]3 years ago
7 0
D is correct cause reflection is used to test minerals magnetisim is not
NeTakaya3 years ago
6 0
A. is the answer.

plus, how would reflecting be a mineral anyway?

hope it helps!
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A long chain of hydrocarbon bonded to cooh is a ________ acid.
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A long chain of hydrocarbon bonded to COOH is a FATTY acid.
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According to Newton’s first law of motion, when will an object at rest begin to move?
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Which of the following features is common to both acids and bases? A. ability to burn skin B. similar taste C. pH measurements g
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<h3>Answer:</h3>

            Correct Option-A (Ability to burn skin)

<h3>Explanation:</h3>

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When 0.620 gMngMn is combined with enough hydrochloric acid to make 100.0 mLmL of solution in a coffee-cup calorimeter, all of t
OleMash [197]

Answer:

The enthalpy change during the reaction is -199. kJ/mol.

Explanation:

Mn(s)+2HCl(aq)\rightarrow  MnCl_2(aq)+H_2(g)

Mass of solution = m

Volume of solution = 100.0 mL

Density of solution = d = 1.00 g/mL

m=1.00 g/mL\times 100.0 mL = 100 g

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

q=m\times c\times (T_{final}-T_{initial})

where,

m = mass of solution = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{final} = final temperature = 23.1^oC

T_{initial} = initial temperature = 28.9^oC

Now put all the given values in the above formula, we get:

q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC

q=2,242.4 J=2.242 kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 2.242 kJ

n = number of moles fructose = \frac{\text{Mass of manganese}}{\text{Molar mass of manganese}}=\frac{0.620 g}{54.94 g/mol}=0.0113 mol

\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

8 0
3 years ago
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