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4 years ago

Help with this question, please!! I don't understand it. SHOW YOUR WORK.

Mathematics

1 answer:

algol [13]4 years ago

6 0

Answer:

d ≈ 14.6 units; M(2.5, 2, 6)

Step-by-step explanation:

The distance formula for 3 dimensions looks a lot like the one for 2 dimensions:

d = √((x2 -x1)^2 +(y2 -y1)^2 +(z2 -z1)^2)

Filling in the given numbers and doing the arithmetic, you find the distance between the points to be ...

d = √((6-(-1))^2 +(-3-7)^2 +(2-10)^2) = √(49+100+64) = √213 ≈ 14.6

The midpoint is the average of the end points:

M = ((6, -3, 2) +(-1, 7, 10))/2 = (5/2, 2, 6)

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3 years ago

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4 years ago

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3 years ago

The rectangle shown has length AC = 32, width

Elena-2011 [213]

Answer:

A. 320

Step-by-step explanation:

See attachment for the figure

in order to determine Area of quadrilateral ABDF, we'll use the formula i.e

Area of quadrilateral ABDF = Area of AECD - Area of ΔBCD - Area of ΔDEF ->eq(1)

whereas, area of AECD = (AC × AE)

Area of ΔBCD = 1/2 (BC x CD)

Area of ΔDEF =1/2 ( EF x ED)

Substituting in eq(1)

eq(1)=>

Area of quadrilateral ABDF = (AC × AE) - 1/2 (BC x CD)- 1/2 ( EF x ED)

=(32 x 20) - 1/2(16 x 20) - 1/2(10 x 32)

= 640 - 160 - 160

= 640 - 320

= 320 square unit

Therefore, the area of quadrilateral ABDF is 320 square unit

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3 years ago