A train has an acceleration of magnitude 0.90 m/s2 while stopping. A pendulum with a 0.55-kg bob is attached to a ceiling of one
1 answer:
The angle of the pendulum with the vertical is
Explanation:
As the train decelerates, the bob of the pendulum will feel a force given by
where
m = 0.55 kg is the mass of the bob
is the magnitude of the acceleration
In the horizontal direction.
The pendulum will be inclined at an angle from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:
(1)
where T is the tension in the string.
We also know that the bob is in equilibrium along the vertical direction: so the vertical component of the tension must be equal to the weight of the bob,
(2)
where is the acceleration of gravity.
Dividing eq.(1) by eq(2), we get:
And therefore, we find the angle:
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<h2>Option A is the correct answer.</h2>
Explanation:
When an elevator moves upward with consonant acceleration a, the overall acceleration on the body is given by
a' = a + g
So acceleration of pendulum is a + g.
We have equation for period of simple pendulum
In normal case a' = g here a' is more.
From the equation we can see that period of simple pendulum is inversely proportional to square root of acceleration.
Since acceleration increases period decreases.
Option A is the correct answer.