<h3>b. ML </h3><h3>c. M</h3><h3>d. Kg</h3>
<h3>Hope it helps...</h3>
The boat is initially at equilibrium since it seems to start off at a constant speed of 5.5 m/s. If the wind applies a force of 950 N, then it is applying an acceleration <em>a</em> of
950 N = (2300 kg) <em>a</em>
<em>a</em> = (950 N) / (2300 kg)
<em>a</em> ≈ 0.413 m/s²
Take east to be positive and west to be negative, so that the boat has an initial velocity of -5.5 m/s. Then after 11.5 s, the boat will attain a velocity of
<em>v</em> = -5.5 m/s + <em>a</em> (11.5 s)
<em>v</em> = -0.75 m/s
which means the wind slows the boat down to a velocity of 0.75 m/s westward.
The distance is 30 km and the displacement is 22.4 km North East
It’s me again lol you’re questions are simple the formula is given in the triangle
The answer is C 39 hz
Please look at the attached image below for the explanation