Answer:
.conserves kinetic energy and momentum
.does not coalesce
.causes much lesser deformation as compared to inelastic
.the two bodies involved; after collision move with separate final velocities.
Explanation:
eg. throwing a ball at a wall
<em>collision</em><em> </em><em>between</em><em> </em><em>a</em><em> </em><em>punch</em><em> </em><em>and</em><em> </em><em>your</em><em> </em><em>nose</em><em>,</em><em>haha</em>
<em>I</em><em> </em><em>guess</em><em> </em><em>that</em><em> </em><em>will</em><em> </em><em>cause</em><em> </em><em>a lot</em><em> </em><em>deformation</em><em>.</em><em>.</em>
<em>.</em>
To turn the aircraft, the pilot uses all three flight controls. The rudder is controlled in the cockpit by foot pedals. When the pilot presses the left pedal, the rudder deflects to the left. This deflection creates more lifting force on the right-hand side of the rudder, which moves the plane's nose to the left.
Answer:
I think, (remember think) it might be 2.0 m/s
Explanation:
If it's wrong I'm truly sorry.
Answer:
C
Im not totally sure but that's what my science teacher taught me sorry if is wrong
Answer:
a. Wavelength = λ = 20 cm
b. Next distance of maximum intensity will be 40 cm
Explanation:
a. The distance between the two speakers is 20cm. SInce the intensity is maximum which refers that we have constructive interference and the phase difference must be an even multiple of π and equivalent path difference is nλ.
Now when distance increases upto 30 cm between the speakers, the sound intensity becomes zero which means that there is destructive interference and equivalent path is now increased from nλ to nλ + λ/2.
This we get the equation:
(nλ + λ/2) - nλ = 30-20
λ/2 = 10
λ = 20 cm
b. at what distance, sound intensity will be maximum again.
For next point calculation for maximum sound intensity, the path difference must be increased (n+1) λ. The distance must increase by λ/2 from the point of zero intensity.
= 30 + λ/2
= 30 + 20/2
=30+10
=40 cm