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3 years ago

What are one of the ways the atmosphere recycle gases through interactions with the biosphere?

Physics

2 answers:

MrRissso [65]3 years ago

4 0

Answer:

B. Through the process photosynthesis

Explanation:

tino4ka555 [31]3 years ago

3 0

Answer:

Though the process photosynthesis

Explanation:

One of the important ways by which the atmosphere recycle gases through interactions with the the biosphere is by photosynthesis.

The biosphere is the living component on the earth. The atmosphere is the gaseous envelope round the earth.

Photosynthesis is the process whereby green plants manufacture their food using carbon dioxide and water in the presence of sunlight to produce glucose and oxygen gas.
This way, atmospheric carbon dioxide is exchanged for oxygen gas.

This way, there is a sustained interaction between the atmosphere and biosphere.

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Jake is helping Fin push a box at a constant velocity up an incline that makes an angle of 30.0° above the horizontal by applyin

andre [41]

Given data

The angle of inclination of the plane is theta = 30 degree

The applied force in the inclined plane is F = 94 N

The distance moved in the inclined plane is d = 2.30 m

The coefficient of kinetic friction is u_k = 0.280

The free-body diagram of the above configuration is shown below:

Here, the normal reaction force on the box is N, the acceleration due to gravity is denoted as g, the friction force on the box is F_f, and the mass of the box is denoted as m.

(a)

The expression for the work done by the pushing force is given as:

$W=Fd$

Substitute the value in the above equation.

$\begin{gathered} W=94\text{ N}\times2.30\text{ m} \\ W=216.2\text{ J} \end{gathered}$

Thus, the work done by the pushing force is 216.2 J.

(b)

The box is moving at the constant velocity, therefore, the pushing force will be equal to the frictional force and the component of the gravitational force in the inclined plane.

$\begin{gathered} F=F_f+mg\sin \theta \\ F=\mu_kN+mg\sin \theta \end{gathered}$

The expression for the normal reaction force is given as:

$N=mg\cos \theta$

The expression for the mass of the box is given as:

$\begin{gathered} F=\mu_k\times mg\cos \theta+mg\sin \theta \\ m=\frac{F}{\mu_kg\cos \theta+g\sin \theta} \end{gathered}$

Substitute the value in the above equation.

$\begin{gathered} m=\frac{94\text{ N}}{0.28\times9.8m/s^2\times\cos 30^o+9.8m/s^2\times\sin 30^0} \\ m=12.9\text{ kg} \end{gathered}$

Thus, the mass of the box is 12.9 kg.

7 0

11 months ago

A body of mass 2 kg is moving in the positive X-Direction with a speed of 4 m/s collides head on with an another body of mass 3

Inga [223]

$m_1=2 \\ m_2=3 \\ v_1=4 \\ v_2=1 \\ v\text{ =speed after collision (to be determined)}.$

The momentul of the system preserves:

$m_1v_1-m_2v_2=(m_1+m_2)v \ \ \ \ \ \Rightarrow \ \ \ \ \ v=\dfrac{m_1v_1-m_2v_2}{m_1+m_2}.$

Ok, we found the speed after the collision.
Now, because the impact is plastic, it produces heat, sound energy and who knows what other forms of energy. We denote all this wasted energy with $E$ .

Now, we write the energy conservation law:

$\dfrac{m_1v_1^2}{2}+\dfrac{m_2v^2_2}{2}=\dfrac{(m_1+m_2)v^2}{2}+E$

From the above equation, you find $E$ , and then conclude that the sound energy can certainly not be greater than this.

8 0

2 years ago

Tensile stress is: A. the strain per unit length. B. the ratio of elastic modulus to strain. C. the ratio of the change in lengt

victus00 [196]

Answer:

D. the same as force. the applied force per cross-sectional area.

Explanation:

Tensile stress of a material is defined as the ratio of the applied force on the material to its cross sectional area. this is expressed mathematically as;

Tensile stress = Force/cross sectional area

Tensile stress = F/A

Force is measured in newton while cross sectional area is measured in m

Hence the unit of Tensile stress is N/m²

6 0

3 years ago

What information in the MSDS would be most important to know at the end of an experiment?

Artemon [7]

The most important information in the MSDS that is useful at the end of an experiment is how to manage or dispose of the waste materials of the experiment. This is important especially if the materials used are toxic. They cannot just be disposed in the sink or the trash bin. They must be disposed in a waste bottle or other methods.

8 0

3 years ago

The same 2000 kg truck formerly traveling at 32 m/s, plows into a

kvasek [131]

Answer: |F| = 1.28 x 10⁵ N

Explanation:

an impulse results in a change of momentum

FΔt = mΔv

F = m(vf - vi)/t

F = 2000(0 - 32) / 0.5

F = -128,000

|F| = 1.28 x 10⁵ N

5 0

3 years ago