Question

For the following reaction, 16.2 grams of carbon dioxide are allowed to react with 45.0 grams of potassium hydroxide. carbon dioxide (g) potassium hydroxide (aq) potassium carbonate (aq) water (l) What is the maximum amount of potassium carbonate that can be formed

Answer 1

Answer:

The maximum amount of potassium carbonate that formed 49.68 g

Explanation:

According to question

                                2 KOH(aq) + CO₂(g) → K₂CO₃(aq) + H₂O(l)

16.2 grams of carbon dioxide are allowed to react with 45.0 grams of potassium hydroxide.

$Moles(KOH)=\frac{Mass}{Molar mass}=\frac{45}{56}= 0.8 moles$

$Moles(CO_{2} )=\frac{16.2}{44} = 0.36 moles$

$(KOH)\frac{Moles}{Stoichiometry}= \frac{0.8}{2} = 0.4\\(CO_{2} )\frac{Moles}{Stoichiometry}= \frac{0.36}{1} =0.36$

So, CO₂ is limiting reagent.

                1 mole CO₂ produce 1 mole K₂CO₃

∴  0.36 mole CO₂ produce 0.36 mole K₂CO₃ or (0.36 x 138)g = 49.68 g