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3 years ago

Repost: What is weathering?

Chemistry

2 answers:

lisov135 [29]3 years ago

5 0

Weathering is a term which describes the general process by which rocks are broken down at the Earth's surface into such things as sediments, clays, soils and substances that are dissolved in water.

Stella [2.4K]3 years ago

4 0

Your drawing looks so good :p

You might be interested in

What is the empirical formula for C12H10O

rjkz [21]

Answer:

Hope this helps

molar mass: 170.21 g/mol

Explanation:

If it did plzz mark brainliest

7 0

4 years ago

I have a question can someone answer these questions for me please?

Kitty [74]

1. C
2. E
3. A
4. B
5. D
I hope that helps <3

8 0

2 years ago

The name "penicillin" is used for several closely-related antibiotics. A 1.2177 g sample of one of these compounds is burned, pr

masya89 [10]

Answer: The empirical formula for the given organic compound is $C_7H_{11}O_2SN$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$S_vN_wC_xH_yO_z+O_2\rightarrow CO_2+H_2O+SO_2+NO$

where, 'v', 'w' 'x', 'y' and 'z' are the subscripts of sulfur, nitrogen, carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.2829g$

Mass of $H_2O=0.1159g$

Mass of $SO_2=0.4503g$

Mass of NO = 0.2109 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

Molar mass of sulfur dioxide = 64 g/mol

Molar mass of nitrogen monoxide = 30 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 2.1654 g of carbon dioxide, $\frac{12}{44}\times 2.1654=0.590g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.6965 g of water, $\frac{2}{18}\times 0.6965=0.077g$ of hydrogen will be contained.

For calculating the mass of sulfur:

In 64 g of sulfur dioxide, 32 g of sulfur is contained.

So, in 0.4503 g of sulfur dioxide, $\frac{32}{64}\times 0.4503=0.225g$ of sulfur will be contained.

For calculating the mass of nitrogen:

In 30 g of nitrogen monoxide, 14 g of nitrogen is contained.

So, in 0.2109 g of nitrogen monoxide, $\frac{14}{30}\times 0.2109=0.098g$ of nitrogen will be contained.

Mass of oxygen in the compound = (1.2177) - (0.590 + 0.077 + 0.225 + 0.098) = 0.2277 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.590g}{12g/mole}=0.049moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.077g}{1g/mole}=0.077moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.2277g}{16g/mole}=0.0142moles$

Moles of Sulfur = $\frac{\text{Given mass of Sulfur}}{\text{Molar mass of sulfur}}=\frac{0.225g}{32g/mole}=0.007moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.098g}{14g/mole}=0.007moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.007 moles.

For Carbon = $\frac{0.049}{0.007}=7$

For Hydrogen = $\frac{0.077}{0.007}=11$

For Oxygen = $\frac{0.0142}{0.007}=2.03\approx 2$

For Sulfur = $\frac{0.007}{0.007}=1$

For Nitrogen = $\frac{0.007}{0.007}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O : S : N = 7 : 11 : 2 : 1 : 1

Hence, the empirical formula for the given compound is $C_7H_{11}O_2S_1N_1=C_7H_{11}O_2SN$

4 0

3 years ago

How many molecules of sodium oxide will be created if 275 grams of sodium reacts with excess oxygen?

musickatia [10]

3.6 x 10²⁴molecules

Explanation:

Given parameters:

Mass of Na = 275g

Unknown:

Number of molecules of Na₂O =

Solution:

Since sodium is the limiting reactant, we first use it to find the number of mole of the Na₂O and transpose it into finding the number of molecules.

Given equation:

4Na + O₂ → 2Na₂O

Since the equation is balanced, let us find the number of moles of Na;

Number of moles = $\frac{mass}{molar mass}$ = $\frac{275}{23}$ = 11.96moles

From the equation of the reaction;

4 mole of Na produced 2 moles of Na₂O

11.96 moles of Na will produce $\frac{11.96 x 2}{4}$ = 6moles

1 mole of a substance = 6.02 x 10²³ molecules

6 moles of Na₂O = 6 x 6.02 x 10²³ molecules = 3.6 x 10²⁴molecules

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

5 0

3 years ago

Magnesium has three naturally occurring isotopes(Mg-24, Mg-25, and Mg-26). The atomic mass and natural abundance of Mg-24 are 23

xxMikexx [17]

Answer:

The answer to your question is below

Explanation:

Data

Atomic mass Abundance

Mg -24 = 23.9850 79%

Mg -25 = 24.9858 10%

Mg - 26= ? ?

Process

1.- Find the abundance of Mg-26

The sum of the abundance of the three isotopes equals 100%

Abundance Mg-24 + Abundance-Mg-25 + Abundance-26 = 100

79 + 10 + Abundance-26 = 100

Abundance Mg-26 = 100 -89

Abundance Mg-26 = 11%

2.- Find the atomic mass of Mg-26, the average atomic mass is 24.31 amu

Average atomic mass = (abundance)(atomic mass- 24) + (abundance)

(atomic mass-25) + (abundance)(atomic mass-26)

24.31 = (0.79)(23.9850)+ (0.10)(24.9858) + (Atomic mass-26)(0.11)

24.31 = 18.94815 + 2.4986 + 0.11(atomic mass-26)

24.31 = 21.4342 + 0.11(atomic mass- 26)

0.11(atomic mass-26) = 24.31 - 21.4342

0.11(atomic mass-26) = 2.8758

Atomic mass-26 = 2.8758/0.11

Atomic mass-26 = 26.1436 amu

8 0

3 years ago

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