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Ratling [72]
3 years ago
11

What's the preview of the scientific method

Chemistry
1 answer:
Dafna11 [192]3 years ago
5 0

Explanation:

overall preview would be an expirement is an empirical procedure that arbitrates competing models or hypothesis ☺️

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The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r
rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

    = 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the  rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

K=Ae^{\frac{-E}{RT}}

If K_1=Ae^{\frac{-E_1}{RT}} -------equation 1     &

K_2=Ae^{\frac{-E_2}{RT}} -------equation 2

\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}

E_1= E_2-RT*In(\frac{K_1}{K_2})

E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})

E_1 = 28957.39292  J/mol

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0
3 years ago
If the speed of an object increases, its kenetic energy
Taya2010 [7]

Answer:

question?

Explanation:

didnt saynsnsns

8 0
3 years ago
Willa holds a pan over a campfire, as shown in the figure below. She feels warmth from the fire.
GarryVolchara [31]

Answer:

thermal radiation/ transfer of heat

6 0
3 years ago
Read 2 more answers
Dilute 0.407M & 2.56L solution to 7.005L. CF?
Alenkinab [10]

Answer:

C₂ = 0.149 M

Explanation:

Given data:

Initial concentration = 0.407 M

Initial volume = 2.56 L

Final volume = 7.005 L

Final concentration = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Initial concentration

V₁ = Initial volume

C₂ = Final concentration

V₂ =Final volume

Now we will put the values.

0.407 M × 2.56 L =  C₂ × 7.005 L

1.042 =  C₂ × 7.005 L

C₂ = 1.042 M.L / 7.005 L

C₂ = 0.149 M

5 0
3 years ago
What is the difference between a state and a microstate of a system?
Brut [27]

Answer:

a) A microstate is a snapshot of positions and speeds at a particular instant.

b) A thermodynamic state is a single possible arrangement of the positions and kinetic energies of the molecules.

c) A thermodynamic state is a set of conditions, usually temperature and pressure, that defines the properties of a bulk material.

d) A microstate is a single possibility for all the positions and kinetic energies of all the molecules in a sample.

e) A thermodynamic state is a set of conditions, usually temperature, volume and number of moles, that defines the properties of a bulk material.

Explanation:

A state of a system in thermodynamics give the properties that a material is been made up, these properties could be pressure, temperature, volumes and others , they are been called thermodynamic property

Microstates helps us to know how molecules is been arranged in single instant. Kinetics energy as well as position of molecules in a particular substance can be known in single instant.

4 0
3 years ago
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