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Bingel [31]
3 years ago
5

What is the formula (with cation and anion charges) for copper (II) hydroxide? ​

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
8 0

Answer:

Cu²⁺(OH)⁻₂

Explanation:

Step 1: Find the symbols for the substances

For copper, see your periodic table. Copper is "Cu".

For hydroxide, see your polyatomic ions chart. Hydroxide is "OH".

Step 2: Find the charges for each element.

Copper (II)'s charge is 2, which is the roman numerals in the brackets.

Hydroxide's charge is -1.

Charges are written as superscripts. You do not need to write "1".

In formulas, write the positively charged atom first.

Cu²⁺(OH)⁻   Put brackets around hydroxide because it has 2 elements.

Step 3: Write the number of atoms.

The number of atoms that an element has is the same as its partner's charge.

The charge of copper is 2, so hydroxide has 2 atoms.

The charge of hydroxide is 1, so copper has 1 atom.

Cu²⁺₁(OH)⁻₂

You do not need to write the "1" for atoms.

Cu²⁺(OH)⁻₂

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Explain the relationship between the following terms: eutrophication, nutrients, dissolved oxygen leads, and algae.
makvit [3.9K]

Answer:

Eutrophication is the enrichment of a body of water with excessive nutrients (nitrogen and phosphorus), which causes algal growth and subsequent decline of dissolved oxygen after decomposition.

6 0
2 years ago
In this reaction, what is the correct coefficient for hydrogen gas? ? h2 + ? o2 ? ? h2o
iragen [17]
To balance a chemical reaction, it is important to remember that the number of atoms of each element in the reactants and the product side should be equal. This is to follows the law of conservation of mass where mass cannot be created or destroyed. So, the total mass that is used to react should have the same value of the total mass of the substances produced from the reactants. The balanced chemical reaction would be written as follows:

<span> 2h2 + o2 = 2h2o

Reactant     =    Product
H = 4           =          4 
O = 2          =           2

Therefore, the correct coefficient for the hydrogen gas would be 2.</span>
6 0
2 years ago
Select all that apply.
deff fn [24]

Answer:

backward, opposite, retrograde

Explanation:

why, i just got it right when i put that.

5 0
2 years ago
Consider the following reaction where Kc = 34.5 at 1150 K:2SO2(g) + O2(g) 2SO3(g)A reaction mixture was found to contain 4.77×10
sukhopar [10]

Answer:

Explanation:

[ so₃] = 4.37 x 10⁻²

[so₂] = 4.77 x 10⁻²

[ o₂] = 4.55 x 10⁻²

Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44

Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.

Kc is always constant . Statement 2 is false.

Statement 3 is false because statement 1 is true.

Qc Is smaller than Kc . So statement 4 is false.

The reaction is not in equilibrium. Statement 5 is false.

3 0
3 years ago
10 pts) A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to re
Natasha2012 [34]

Answer: The molarity of the borax solution is 0.107 M

Explanation:

The neutralization reaction is:

Na_2B_4O_7.10H_2O+H_2SO_4(aq)\rightarrow Na_2SO_4+4H_3BO_3+5H_2O

According to neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of H_2SO_4 = 2

n_2 = acidity of borax = 2

M_1 = concentration of H_2SO_4 = 1.03 M

M_2 = concentration of borax =?

V_1 = volume of H_2SO_4  = 2.07ml

V_2 = volume of borax = 20.0 ml

Now put all the given values in the above law, we get the molarity of borax:

(2\times 1.03\times 2.07)=(2\times M_2\times 20.0)

By solving the terms, we get :

M_2=0.107M

Thus the molarity of the borax solution is 0.107 M

7 0
3 years ago
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